A rocket of mass 6.0 kg takes off from the ground and goes straight up. During the first 100 meters of its ascent, the engine exerts a 80 newton upward force on the rocket. a) how much work does the engine do on the rocket during those first 100 meters? b) Assuming kinetic and potential are the only kinds of energy the rocket gains, how much kinetic energy does the rocket have at the moment it's 100 meters above the ground? (Hint: You'll need to use a formula for gravitational potential energy but not a formula for kinetic energy. Think about the relationship between work and energy. To keep the math less messy, approximate g as 10 m/s^2.) c) At height 100 meters, the rocket has 1850 joules of kinetic energy, which is less than your part b answer. Is energy not conserved , or is something else going on? Where are the "missing" joules?
Answers
The answer given in part b is 1850 J, which is less than the calculated value of 240,000 J.
a) The work done by the engine on the rocket during the first 100 meters can be calculated using the formula:
W = F * d
where W is the work done, F is the force exerted by the engine, and d is the distance traveled by the rocket. In this case, the force exerted by the engine is 80 N and the distance traveled by the rocket is 100 meters. So the work done by the engine is:
W = 80 N * 100 m = 8000 J
b) To calculate the kinetic energy of the rocket at a height of 100 meters, we can use the formula:
KE = 1/2 * m * \(v^2\)
where KE is the kinetic energy, m is the mass of the rocket, and v is its velocity. In this case, the mass of the rocket is 6.0 kg and its initial velocity is zero, so its velocity at a height of 100 meters is given by:
v = √(2 * g * h)
where g is the acceleration due to gravity (approximated as 10 \(m/s^2\)) and h is the height above the ground. So the velocity of the rocket at a height of 100 meters is:
v = √(2 * 10 * 100) = 100 m/s
Using the formula for kinetic energy, we can calculate the kinetic energy of the rocket at a height of 100 meters as:
KE = 1/2 * 6.0 kg * (100 \(m/s)^2\) = 30,000 J
So the kinetic energy of the rocket at a height of 100 meters is greater than the work done by the engine during the first 100 meters of its ascent, as expected.
c) The energy gained by the rocket during the ascent can be calculated as the sum of the work done by the engine and the change in gravitational potential energy:
ΔE = W + mgh
where ΔE is the energy gained, m is the mass of the rocket, g is the acceleration due to gravity, h is the height above the ground, and W is the work done by the engine. In this case, the mass of the rocket is 6.0 kg, the acceleration due to gravity is \(10 m/s^2,\) and the height of the rocket is 100 meters. So the energy gained by the rocket during the ascent is:
ΔE = 8000 J + 6.0 kg * (100 \(m/s)^2\) = 240,000 J
However, the answer given in part b is 1850 J, which is less than the calculated value of 240,000 J.
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Related Questions
11. A collection of a small group of factors that are related is known as a(n)
a. system
b. hypothesis
c. prediction
d. objective
Answers
Answer:
system
Explanation:
they are all put together as one, and they are a group
determine the magnetic flux through the center of a solenoid having a radius r = 2.10 cm. the magnetic field within the solenoid is 0.52 t.
Answers
In conclusion, the magnetic flux through the center of a solenoid with a radius of 2.10 cm and a magnetic field of 0.52 T is 0.00072 Wb.
To determine the magnetic flux through the center of a solenoid with a radius of 2.10 cm and a magnetic field of 0.52 T, we need to use the formula for magnetic flux, which is Φ = B × A, where B is the magnetic field and A is the area of the surface perpendicular to the field.
Since the solenoid has a cylindrical shape, we can use the formula for the area of a circle, which is A = πr^2, where r is the radius of the circle. Therefore, the area of the solenoid is A = π(0.021)^2 = 0.001385 m^2.
Substituting the values of B and A into the formula for magnetic flux, we get Φ = (0.52 T) × (0.001385 m^2) = 0.00072 Wb.
Therefore, the magnetic flux through the center of the solenoid is 0.00072 Wb.
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Ingrid is participating in a relay race. While jogging at 9 km/h, she tosses a relay stick at 16 km/h to her teammate, who is standing still. How fast is the relay stick moving relative to Ingrid
Answers
The relay stick is moving at 7 km/h relative to Ingrid.
Ingrid is jogging at a speed of 9 km/h and tosses the relay stick at a speed of 16 km/h to her team mate who is standing still.
The relative velocity of the relay stick with respect to Ingrid can be calculated using the relative velocity formula.
The formula states that the relative velocity of the stick with respect to Ingrid is equal to the difference between the velocities of the stick and Ingrid.
Therefore, the relative velocity of the relay stick with respect to Ingrid is 16 km/h - 9 km/h, which is equal to 7 km/h.
This means that the relay stick is moving at 7 km/h relative to Ingrid.
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which trophic level has the least available energy in kilojoules in this food web?
Answers
The highest trophic level has the least available energy in kilojoules.
Even though the food web is not shown in the question, but we know that energy decreases steadily as it is passed on from one trophic level to the next according to the second law of thermodynamics.
Energy enters into the system from the sun. The primary producers utilize this energy to produce food. As plants are eaten by animals, this energy is transferred along the food web an diminishes at each higher trophic level.
At the highest trophic level, the the least available energy in kilojoules in this food web is found.
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An 84 N force has been applied to a block to the right but the block is moving vertically! How weird. How
much work has been done to the block? Explain your reasoning.
Answers
No work is being done on a block travelling vertically if an 84 N force has been applied to the right side of the block horizontally. Work is described as the result of applied force and object movement in the force's direction.
There is no change in the force's direction in this situation since the block is travelling vertically and the force is exerting itself horizontally. Therefore, there has been no work done on the block.
This situation might appear strange, but it serves to illustrate the notion that labour can only be accomplished when the applied force and displacement are in harmony.
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For motion along a straight line it ______ possible for speed to be constant while acceleration is not zero.
Answers
For motion along a straight line it NOT possible for speed to be constant while acceleration is not zero.
If the acceleration is not zero means that the speed has changed whether to higher (positive acceleration) or lower (negative acceleration) if the object is slowing down.
When the speed is constant, it means that the velocity at the beginning of the motion and the velocity at the ending of the motion are the same.
What is acceleration?It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2
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State four factors that are affected by different substances interacting with different EM waves.
Answers
The four factors that can be affected by different substances interacting with different EM waves are absorption, reflection, transmission, and emission.
What are the four factors that affecting EM Waves?The four factors that can be affected by different substances interacting with different EM waves are;
Absorption: When a substance interacts with an EM wave, it can absorb some or all of the energy of the wave.
Reflection: Instead of being absorbed, some EM waves can bounce off a substance and reflect back.
Transmission: When EM waves pass through a substance, they can be affected by the properties of the substance.
Emission: Some substances can emit EM waves of their own when they interact with other waves.
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A 2.0 kg box is pulled along a frictionless, horizontal surface by a force that makes an angle of 30 degrees with the ground. If the box is pulled a distance of 4.0 meters and changes speed from 1.0 m/s to 3 m/s, what was the magnitude of the force on the box?
Answers
Answer:
2 N
Explanation:
v = Final velocity = 3 m/s
u = Initial velocity = 1 m/s
s = Displacement = 4 m
m = Mass of box = 2 kg
Acceleration of the box is
\(v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{3^2-1^2}{2\times 4}\\\Rightarrow a=1\ \text{m/s}^2\)
Force is given by
\(F=ma\\\Rightarrow F=2\times 1\\\Rightarrow F=2\ \text{N}\)
The force on the box is 2 N.
A remote controlled toy car starts from rest and begins to accelerate in a straight line. The figure below represents "snapshots" of the car's position at equal 0.5 s time intervals. (Assume the positive direction is to the right. Indicate the direction with the sign of your answer.)
(a) What is the car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s?
(b) Using data from t = 1.0 s to t = 2.0 s, what is the car's acceleration (in m/s2) at t = 1.5 s?
(c) Is the car's speed increasing or decreasing with time?
Answers
Answer:
Explanation:
is this marked??
(a). The car's average velocity between t = 1.0s to t = 1.5s will be - \(1\;m/s\)
(b). The car's acceleration at t = 1.5s will be - \(0.4\;m/s^{2}\)
(c). Car's speed is increasing with time.
We have a a remote controlled toy car that starts from rest and begins to accelerate in a straight line.
We have to determine -
The car's average velocity (in m/s) in the interval between -t = 1.0 s to t = 1.5 s.
The car's acceleration at t = 1.5 s.Determining whether car's speed increasing or decreasing with time.What is Acceleration?The rate of change of velocity with respect to time is called Acceleration. Mathematically -
\($a=\frac{dv}{dt}\)
According to the question, we have the following data for the Car -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m
PART - A
The car's average velocity between t = 1.0s to t = 1.5s will be -
\($v_{avg} = \frac{0.9-0.4}{1.5-1}= 1 m/s\)
PART - B
Velocity at t = 1.5 s will be -
\($v(1.5)=\frac{0.9}{1.5}= 0.6\;m/s\)
The car's acceleration at t = 1.5s will be -
\($a(1.5) = \frac{v}{t} = \frac{0.6}{1.5} = 0.4\;m/s^{2}\)
PART - C
Since, the acceleration of the car is positive, this means that the car is accelerating in the forward direction. Hence, its speed is increasing with time.
[ The following data was missing in your answer. The complete question would include this data also -
t = 0s → x = 0m
t = 0.5s → x = 0.1m
t = 1.0s → x = 0.4m
t = 1.5s → x = 0.9m
t = 2.0s → x = 1.6m ]
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what is the magnitude of the electric field along the positive z axis? use k in your answer, where k
Answers
The magnitude of the electric field along the positive z axis due to the ring is equal to Ez = kqz/√(z² + a²)^{3/2}.
Given the following data:
Radius of ring = a.
Charge of ring = q.
Coulomb's constant, k = = 1/4πε₀.
What is an electric field?An electric field can be defined as a region in which charged particles are placed with force being applied on the particle as a result of the field.
How to determine the magnitude of the electric field?In order to determine the magnitude of the electric field along the positive z axis, we would apply Coulomb's law in order to find the electric field due to a point charge:
\(E = k\frac{q}{r^2}\)
Where:
q represent the charge.r is the distance between two charges.k is Coulomb's constant.Note: The value of r is equal to √(z² + a²) and cosθ is equal to z/√(z² + a²).
Substituting the value of r into Coulomb's law, we have;
\(E = k\frac{q}{(\sqrt{z^2 + a^2}) ^2}\)
Along the z-direction, the electric field is given by:
dz = dEcosθ
Integrating, we have:
∫dz = ∫dEcosθ
Ez = Ecosθ
\(E_z = (\frac{kq}{(\sqrt{z^2 + a^2}) ^2})\frac{z}{\sqrt{z^2 + a^2}} \\\\E_z = \frac{kqz}{(\sqrt{z^2 + a^2}) ^\frac{3}{2} }\)
Ez = kqz/√(z² + a²)^{3/2}.
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Complete Question:
Consider a uniformly charged ring in the xy plane, centered at the origin. The ring has radius a and positive charge q distributed evenly along its circumference. What is the magnitude of the electric field along the positive z axis due to the ring? Use k in your answer, where k = 1/4πε₀
The jet engine fitted to a small aircraft uses 35 kg/s of air when the aircraft is flying at a speed of 800 km/h. The jet efflux velocity is 590 m/s. If the pressure on the engine discharge plane is assumed to be equal to the ambient pressure and if effects of the mass of the fuel used are ignored, find the thrust developed by the engine
Answers
The thrust developed by the engine is 16,209.3 N.
When an engine thrust forward and a reaction force acts in the opposite direction, a propulsion system propels an object forward. The airplane's propulsion system, such as the jet engine, propels it forward. The formula for calculating the thrust of a jet engine is given by the equation:
F = ma + (V2 - V1)Q Where: F is the engine's thrust, a is the acceleration of the gases coming out of the engine, V1 is the velocity of the air entering the engine, V2 is the velocity of the exhaust gases, and Q is the mass flow rate (kg/s) of the air flowing through the engine.
F = ma + (V2 - V1)Q
The mass flow rate is given by the question as Q = 35 kg/s. The efflux velocity is given by the question as
V2 = 590 m/s
The airspeed of the aircraft is given by the question as
V1 = 800 km/h = 800/3.6 m/s = 222.22 m/s
F = ma + (V2 - V1)Q
F = (35 * 590) + (222.22 - 590)35
F = 20530 + (- 36739.3)
F = -16209.3 N
The negative sign implies that the thrust acts in the opposite direction of motion of the airplane. Therefore, the engine thrust is 16,209.3 N in magnitude.
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How much force is applied if a 130 kg mass is accelerated at 5 m/s^2
Answers
Answer:
650N
Explanation:
f = ma
130kg x 5 m/s^2 = 650N
When cattle are processed, what is the most likely use for the animals' skin?
O Gum
Fertilizer
O Upholstery
O Leather
Answers
When cattle are processed, the most likely use for the animals' skin is in
the production of Leather.
Animals used for Leather productionCattleGoatCrocodile etc.The commonly used animals in leather production is however cattle and
they amount for a large percentage of leather present today. They also
involve various techniques such as tanning and crusting to ensure
conversion to leather.
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by which method does the structure at b release neurotransmitter?
Answers
Answer:
The influx of Ca2+ triggers the release of neurotransmitters stored in synaptic vesicles (B) by exocytosis.
hope this helps.
840 inches to cm show work pls
Answers
Toy cars 1, 2, and 3 are launched horizontally with the trajectories shown below. Cars 1 and 2
are launched from a 15 m high cliff, while Car 3 is launched from a 30 m high cliff. We can
ignore air friction.
Answers
Initial launch speed of the cars are in order as Vcar 1 = Vcar 2< Vcar 3
Speed (often abbreviated as "s") is a scalar variable that describes how much an object's location changes over time or how much it changes per unit of time. The average speed of an item in a period of time is the distance traveled by the object divided by the duration of the period.
Time divided by distance are the speed-related metrics.. The meter per second (m/s) is the SI unit of speed, while the kilometer per hour (kph) is the most often used unit of speed in daily life.
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A hockey puck with a mass 0.160 kg is at rest on the horizontal, frictionless surface of a rink. A player applies a force of 0.250 N to the puck, parallel to the surface of the ice and continues to to apply this force for 2.00 s.
What is the position and speed of the puck at the end of that time?
Answers
The position of the puck at the end of that time is 3.125 m and the speed of the puck at the end of that time is 3.125 m/s.
The position and speed of the puck at the end of that time can be determined using the equations of motion for constant acceleration.
First, we need to find the acceleration of the puck. The acceleration can be found using Newton's second law of motion, which states that force equals mass times acceleration:
F = m*a
Rearranging the equation to solve for acceleration gives:
a = F/m
Plugging in the given values for force and mass gives:
a = 0.250 N / 0.160 kg = 1.5625 m/s^2
Next, we can use the equation for the final position of an object undergoing constant acceleration:
x = x0 + v0*t + (1/2)*a*t^2
The initial position (x0) and initial velocity (v0) of the puck are both zero, so the equation simplifies to:
x = (1/2)*a*t^2
Plugging in the values for acceleration and time gives:
x = (1/2)*(1.5625 m/s^2)*(2.00 s)^2 = 3.125 m
Finally, we can use the equation for the final velocity of an object undergoing constant acceleration:
v = v0 + a*t
Again, the initial velocity (v0) is zero, so the equation simplifies to:
v = a*t
Plugging in the values for acceleration and time gives:
v = (1.5625 m/s^2)*(2.00 s) = 3.125 m/s
So, the position of the puck at the end of that time is 3.125 m and the speed of the puck at the end of that time is 3.125 m/s.
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A student walks 1.0 km due south. Then she runs 2.o km due west. Find the magnitude of the student's resultant displacement .
Answers
Check this..
Thank you ..
distance traveled divided by average speed is the formula for what
Answers
Answer:
Time
Explanation:
As
Speed = distaance / time
S = d/t
t = d/s
Explain:
M/m/s meter by meter
=s
a 75.0kg man pushes on a 500,000t wall for 250s but it does not move. how much work does he do on the wall?
Answers
Answer:
✓ No work Explanation: Work is equal to a force times a displacement (parallel to the force) $$W=F*D$$ It is energy that causes a mass to be moved.
Explanation:
How is a brown object appear brown when white light is reflected on it even though brown is not a colour component of white light?
Answers
Why does time seem to flow only in one direction? ...
Answers
Answer:
Mass is relative too. Thus, as much fuel as you pack you will never reach the velocity of light. At the velocity of light, if you were somehow to reach it, your mass will be infinite and it will so require infinite force to push you, so no going beyond that speed. This is the reason time flows in a single direction.
Explanation:
Which of the following is a characteristic of a mechanical wave but not a characteristic of an electromagnetic wave?
Answers
Mechanical waves have a crest but no trough is a characteristic of a mechanical wave but not a characteristic of an electromagnetic wave.
What is an electromagnetic wave?The waves that are related to both electricity and magnetism are known as electromagnetic (EM) waves. These waves are made up of time-varying electric and magnetic fields that travel over space.
Mechanical waves have a peak but no dip, which is a mechanical wave characteristic but not an electromagnetic wave characteristic.
Hence, mechanical waves have a crest but no trough is a characteristic of a mechanical wave but not a characteristic of an electromagnetic wave.
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Why can’t security gates detect plastic bomb ?
Answers
Answer:
The plastic is too much like other things that are allowed. Sometimes it is too thin, as well. Or sometimes the gates are just not that modern and advanced enough to detect them.
What is the momentum of a 45-kg quarterback moving eastward at 15
m/s?
Answers
Answer:
Given
mass (m) =45kg
velocity (v) =15m/s
momentum (p) =?
Form
p=mv
=45x 15
p=675kg.m/s
the momentum =675kg.m/s
The source of all magnetic fields is:
- moving charges
- the earth's gravity
- the aurora borealis
- solar fields
Answers
Answer:
Moving charges
Explanation:
The source of all magnetic fields is moving electric charge: whether it is current in a wire, unpaired electrons in an atomic orbital, convection currents in the earth's liquid nickle /iron core, plasma in the sun, etc. moving electric charge is the source of all magnetic fields.
A 10.0-kg crate slides along a raised horizontal frictionless surface at a constant speed of 4.0 m/s. The crate then slides down a frictionless incline and across a second, roughened horizontal surface as shown in the figure. What is the kinetic energy of the crate as it reaches the lower surface?
Answers
The kinetic energy of the crate as it reaches the lower surface is 80 J
Kinetic energy is the energy possed by an object in motion. Mathematically, the kinetic energy can be expressed as follow:
KE = ½mv²
With the above formula, the kinetic energy of the crate can be obtained as follow:
Mass (m) = 10 KgVelocity (v) = 4 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 10 × 4²
KE = 5 × 16
KE = 80 J
Therefore, the kinetic energy of the crate is 80 J
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What are the rated voltages and currents of the primary and the secondary windings (considered independently)
Answers
The rated voltages and currents of the primary and secondary windings, when considered independently, depend on the specific transformer. The rated voltage of the primary winding refers to the voltage at which the transformer is designed to operate on the input side.
It is typically determined based on the power system voltage level in which the transformer is connected. The rated current of the primary winding is the maximum current that the primary winding can safely carry without exceeding its design limits.
Similarly, the rated voltage of the secondary winding is the voltage at which the transformer is designed to deliver power on the output side. This voltage level is determined based on the desired output voltage for the intended application. The rated current of the secondary winding is the maximum current that the secondary winding can safely supply to the connected load.
It is important to note that the rated voltages and currents of the primary and secondary windings of a transformer are specified by the manufacturer and can vary depending on the specific transformer design and application.
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10. What is the acceleration due to gravity at a location
where a 15.0-kilogram mass weighs 45.0 newtons?
1) 675 m/s2
2) 9.81 m/s2
3) 3.00 m/s2
4) 0.333 m/s2
Answers
Suppose you are visiting the equator. It is noon. The Sun is at its highest point in the sky for the day, which is directly over your head You call a friend on the phone and she says it is also noon where she is but the Sun is not directly overhead at that location and time. It is a little lower in the sky for her Compare the longitude and latitude where you are with the longitude and latitude where your friend is Are they alike or different? How do you know?
please answer all questions i promise ill mark you brainlest
Answers
Answer:
You as well as your mate seem to be at different latitudes and a similar longitude. Further explanation is given below.
Explanation:
Even though it is noon period and indeed the sun has been in equator situation right underneath of you. Then the day was the first day of the equinox. Except for your mate, whoever you named, said it was noon elsewhere, too. So, this means that she is the same length as you, too. Time is something like a line of longitude is still the same, varying with longitude transition. Even, your friend mentioned, at noon yesterday, the sun isn't passing overhead at this same spot. She said that the sun becomes significantly dependent on the wavelength, meaning that it could be further from the equator at that same low latitude. But it would be in the south as well as north Hemisphere, although both are probable. Since the sub-solar position would be at the equator, the higher it is much further from the equator, the lower the sun's height throughout the atmosphere.So, perhaps you as well as your mate seem to be at different latitudes and a similar longitude.