Based on the chemical properties of the residues, determine which sequences would exhibit which structural properties. Most likely an amphipathic Most likely an amphipathic a helix Most likely a turn/loop Not amphipathic B sheet Lys-Ser-Thr-Asn-Glu-Gln-Asn- Ser-Arg Asn-Leu-Ala-Asp-Ser-Phe-Arg- Gln-Ile Lys-In-Asn-Glu-Pro-Arg-Ala- Asn-Glu Arg-Phe-Gln-Ile-His-Val-Gln- Phe-Glu Answer Bank

a)Dissolve 1.34 g of KBr in 0.75 L of water to get the solution, b)Dissolve 2.62 g of KBr in 122.38 g (or 122.38 mL) of water to get the solution, c)Dissolve 244.2 g of KBr in 1790.8 g (or 1.7908 L) of water to get the solution, d)Dissolve 10.14 g of KBr in 0.568 L of water to get the solution

Molar mass of KBr = 119 g/mol

(a) Concentration = moles of KBr/volume

1.5 x 10-2 = moles of KBr/0.75

moles of KBr = 0.01125 mol

mass of KBr = moles x molar mass

= 0.01125 x 119 = 1.34 g

Dissolve 1.34 g of KBr in 0.75 L of water to get the solution

(b) mass of water + mass of KBr = 125 g = 0.125 kg

=> mass of water = 0.125 - mass of KBr

moles of KBr = mass of KBr/molar mass

Molality = moles of KBr/mass of water in kg = mass of KBr/(molar mass of KBr x (0.125 - mass of KBr)

0.180 = mass of KBr/(0.119 x (0.125 - mass of KBr))

mass of KBr = 0.00262 kg = 2.62 g

mass of water = 125 - 2.62 = 122.38 g

Dissolve 2.62 g of KBr in 122.38 g (or 122.38 mL) of water to get the solution

(c) Mass of solution = density x volume

= 1.10 x 1850 = 2035 g

mass of KBr = 12/100 x 2035 = 244.2 g

mass of water = 2035 - 244.2 = 1790.8 g

Dissolve 244.2 g of KBr in 1790.8 g (or 1.7908 L) of water to get the solution

(d) KBr + AgNO3 => AgBr + KNO3

Moles of KBr = moles of AgBr = mass of AgBr/molar mass of AgBr

= 16.0/187.77 = 0.08521 mol

mass of KBr = moles x molar mass

= 0.08521 x 119 = 10.14 g

volume of water = moles/concentration

= 0.08521/0.150 = 0.568 L

Dissolve 10.14 g of KBr in 0.568 L of water to get the solution

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P-aminophenol has a molar mass of 109.13 g/mol. Acetaminophen has a molar mass of 151.17 g/mol. Acetic anhydride has a capacity of 1.1 mL.

The mass of acetaminophen, stated as 0.157g, must be multiplied by the molar mass of acetaminophen to get the theoretical yield. It weighs 151.2g in this case. The theoretical yield thus becomes 0.217g.

A measurement called production yield is obtained by dividing the number of high-quality parts produced by the total number of parts started in production.

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Answer:

hypothesis testing is usually used to assess the plausibility of a hypothesis by using sample data

Explanation:

The equilibrium constant for the reaction 2NO(g)+Br₂(g)⇌2NOBr(g) is Kc=2.1×10⁻²Kc=2.1×10⁻² at a certain temperature. Then, Kc for the reaction NOBr(g) ⇌ NO(g) + 1/2Br₂(g) will be approximately 47.62.

To calculate the equilibrium constant, Kc, for the reaction:

NOBr(g) ⇌ NO(g) + 1/2Br₂(g)

We will use the relationship between the equilibrium constants of forward and reverse reactions. For the reverse reaction, which is the given reaction:

2NO(g) + Br₂(g) ⇌ 2NOBr(g)

The equilibrium constant is Kc = 2.1 × 10⁻².

Now, let's determine the equilibrium constant, Kc', for the forward reaction using the relationship:

Kc' = 1 / Kc

Kc' = 1 / (2.1 × 10⁻²)

Kc' ≈ 47.62

Therefore, the Kc will be 47.62.

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The heat of combustion per gram of propane is approximately -46.5 kJ/g.

a) To calculate the mass of O2 required, we need to use the thermochemical equation and the given heat requirement. From the equation, we see that the molar ratio of C3H8 to O2 is 1:5. Therefore, for every 1 mole of C3H8, we need 5 moles of O2.

The molar mass of O2 is approximately 32 g/mol. We can use the molar mass to convert moles of O2 to grams.

Given that the heat requirement is 1530 kJ, we can set up a proportion:

(5 moles O2 / 1 mole C3H8) = (x grams O2 / 1530 kJ)

Solving for x, we get:

x = (5 moles O2 / 1 mole C3H8) * (32 g O2 / 1 mole O2) * (1530 kJ / 1)

x = 244,800 g

Therefore, approximately 244,800 grams (or 245 kg) of O2 must react to produce 1530 kJ of heat.

b) To calculate the mass of CO2 emitted, we use the same approach. From the thermochemical equation, the molar ratio of C3H8 to CO2 is 1:3. Therefore, for every 1 mole of C3H8, we get 3 moles of CO2.

Using the same proportion as in part a), but substituting CO2 for O2:

(3 moles CO2 / 1 mole C3H8) = (y grams CO2 / 1530 kJ)

Solving for y, we get:

y = (3 moles CO2 / 1 mole C3H8) * (44 g CO2 / 1 mole CO2) * (1530 kJ / 1)

y = 201,240 g

Therefore, approximately 201,240 grams (or 201 kg) of CO2 are emitted into the atmosphere during the grilling of the meat.

c) The heat of combustion per gram of propane can be determined by dividing the heat of combustion (AH) by the molar mass of propane.

Given AH = -2044 kJ and the molar mass of propane (C3H8) is approximately 44 g/mol, we can calculate the heat of combustion per gram:

Heat of combustion per gram = -2044 kJ / 44 g

Heat of combustion per gram = -46.5 kJ/g

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Rhombic sulfur and monoclinic sulfur are the two primary allotropes of sulfur.

Allotropes are various versions of the same element that can exist in various crystal shapes or physical states. An element's several allotropes each have different physical and chemical characteristics. For instance, carbon can exist in a variety of allotropes, each with a unique set of properties and applications, such as diamond, graphite, and fullerene.

The most prevalent type of sulfur is rhombic sulfur, which is yellow in hue. It is made up of S8 rings that have been puckered into a chair-like conformation. Rhombic sulfur is insoluble in water and stable at temperatures lower than 96°C. Insecticides, fertilizers, and sulfuric acid are all made with it.

Compared to rhombic sulfur, monoclinic sulfur is less frequent and denser. Although it has golden crystals as well, they resemble needles. Monoclinic sulfur can dissolve in some solvents, such as carbon disulfide, and is stable above 96°C. Both the vulcanization of rubber and the creation of gunpowder use it.

The 58 molecules that make up both types of sulfur are the same, but their crystal shapes and physical characteristics are different. Other allotropes of sulfur, like amorphous sulfur and plastic sulfur, which have different structures and characteristics from rhombic and monoclinic sulfur, can also occur.

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The balanced chemical equations are as  follows:

14. C₂H₄ + 3 O₂ -> 2CO₂ + 2H₂O

15. 2NaHCO₃ -> Na₂CO₃ + H₂O + CO₂

16. 3Cl₂ + 2NaBr -> 2NaCl + Br₂

17. 3Na₂S + 2NaCl + 3H₂O -> 5NaCl + H₂S + 3O₂

Balanced equations are equations of chemical reactions that ensure that the law of conservation of mass is true.

In a balanced equation, the number of atoms of each element on both sides of the equation is equal.

The given chemical equations are balanced as follows;

14.  Place 3, 2, and 2 before O₂, CO₂, and H₂O respectively.

C₂H₄ + 3 O₂ -> 2 CO₂ + 2 H₂O

15. Place 2 in front of NaHCO₃.

2 NaHCO₃ -> Na₂CO₃ + H₂O + CO₂

16. Place 3, 2, and 2 in front of Cl₂, NaBr, and NaCl respectively.

3Cl₂ + 2NaBr -> 2NaCl + Br₂

17. Place 3, 2, 3, 5, and 3 in front of Na₂S, NaCl, H₂O, NaCl, and O₂ respectively.

3Na₂S + 2NaCl + 3H₂O -> 5NaCl + H₂S + 3O₂

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the proper equipment need to perform both a filtration procedure and heating of a substance in a beaker procedure are beaker , bunsen burner, filter paper, funnel, safety goggles.

To perform a filtration and heating of a substance in a beaker, the following equipment is typically needed:

Beaker: A beaker is used to hold the substance and is typically made of glass or plastic.

Bunsen Burner: A Bunsen Burner is used to heat the substance in the beaker.

Filter paper: Filter paper is used to filter the substance during the filtration procedure.

Funnel: A funnel is used to pour the substance into the filter paper for filtration.

Hot Plate or Heating Mantel: A hot plate or heating mantle is used to heat the beaker and the substance contained in it.

Stirring Rod: A stirring rod is used to mix the substance in the beaker during heating.

Safety goggles: Safety goggles should be worn to protect the eyes from any splashes or fumes produced during the heating process.

Heat-resistant gloves: Heat-resistant gloves should also be worn to protect the hands from the hot beaker and any splashes of the substance.

It is important to use proper equipment and follow proper safety procedures when performing any laboratory procedures, including filtration and heating of substances.

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C₁H₂O₁ is the empirical formula for the substance. The substance has the molecular formula 4 (C₁H₂O₁).

The empirical formula is the most basic whole number ratio of atoms in a given compound. The empirical formula is typically applied to simply display the elements that make up a molecule. This is helpful if you want to quickly identify the elements you're working with. The molecular formula comes in handy when you want to figure out how many atoms of each element are contained in the compound.

Element   %   Atomic mass   Relative no. of atoms  Simplest whole ratio

C          40.6       12                   40.6/12 = 3.3                  3.3/3.3 = 1      

H          5.1          1                      5.1/1 = 5.1                        5.1/3.3 = 2

O         54.2       16                    54.2/16 = 3.3                   3.3/3.3 = 1    

The compound's empirical formula is C₁H₂O₁ or CH₂O

Molecular formula = Empirical formula × n

n = Molecular weight/ Empirical weight

n = 118.034/30

n = 4

Molecular formula = n × Empirical formula

Molecular formula = 4 (C₁H₂O₁)

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The increase in pressure when a basketball is pumped up is caused by the change in the number of molecules (optionC).

When air is pumped into a basketball, the air molecules are forced into a smaller space, which increases the number of molecules in that space. This increase in the number of molecules leads to an increase in the pressure of the gas within the ball.To better understand why this is the case, we can use the ideal gas law, which describes the behavior of gases under various conditions. The ideal gas law is expressed as PV = nRT, where P is pressure, V is volume, n is the number of molecules, R is the gas constant, and T is temperature.
When air is pumped into a basketball, the volume of the ball remains the same (assuming the ball is rigid and does not expand), and the temperature of the air inside the ball does not change significantly. Therefore, according to the ideal gas law, the only way the pressure can increase is if the number of molecules (n) increases.
This increase in pressure is what makes the ball bouncy and allows it to be used for games and activities. It is important to note that overinflating a basketball can lead to a rupture or bursting of the ball due to the excessive pressure created by the increased number of molecules.

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The statements which is true about the reactants from the given simulation above is: It involves the breaking of chemical bonds.

The correct answer choice is option c

For a chemical reaction to occur, the bond between the reacting substances breaks either by covalent or electrovalent bonding in order to form new substance.

So therefore, reactants usually break chemical bonds duringchemical reaction.

Complete question:

A chemical reaction causes the chemical compositions of substances to change. Reactants are substances that enter into a reaction, and products are substances produced by the reaction

Which of the following are the reactants for this simulation? Select all that apply

a. A chemical reaction results to formation of new bonds

b. A chemical reaction involves the formation of new substance.

c. It involves the breaking of chemical bonds

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In the reaction, C\(_6\)H\(_{121}\)O\(_{6}\) + 6O\(_2\) → 6CO\(_2\)+ 6H\(_2\)O, O\(_2\) is the limiting reagent. Therefore, the correct option is option B.

The compounds that are completely consumed during the course if a chemical reaction are known as limiting reagents. Other names for them are limiting reactants and limiting agents. The stoichiometry if chemical processes states that a specific number of reactants are required for the process of reaction to be complete.

The reaction's stopping point is often determined by this reactant. The reaction stoichiometry is used to compute the precise quantity of reactant which would be required for a reaction with another element. Not the total amount of the reactants present, but the mole ratio determines the limiting reagent. In the reaction, C\(_6\)H\(_{121}\)O\(_{6}\) + 6O\(_2\) → 6CO\(_2\)+ 6H\(_2\)O, O\(_2\) is the limiting reagent.

Therefore, the correct option is option B.

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In pulmonary ventilation, the movement of gases is between the atmosphere and the alveoli of the lungs.

It is the process of inhalation and exhalation of air from the lungs. This happens because of the difference of pressure due to contraction and relaxation.

Inspiration occurs intrapleural cavity enlarges due to diaphragm's contraction which pulls it down. intrapleural cavity also occurs when ribs are elevated.

In  pulmonary ventilation, three different pressures are included; Atmospheric pressure, Interalveolar pressure, Intrapleural pressure.

The pressure outside the body is known as atmospheric pressure. Pressure inside the alveoli of the lungs is known Interalveolar pressure. The pressure in the  pleural cavity is known as Intrapleural pressure.

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Answer:

A. Students made a measurement error, because ending with more products is impossible.

Explanation:

The law of conversation of matter tells us that in a chemical reaction, matter is never created or destroyed, it's simply converted from one form to another. So the mass of reactants should always equal the mass of the products in a chemical reaction. If there is excess mass in the product, the students have made an error of some kind.

Answer:

Dalton's 5 postulates

All matter consists of indivisible particles called atoms.

Atoms of the same element are similar in shape and mass, but differ from the atoms of other elements.

Atoms cannot be created or destroyed.

Atoms of different elements may combine with each other in a fixed, simple, whole number ratios to form compound atoms.

Explanation:

All but one of the halides will produce a precipitate with Silver.

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Answer:

D. Fire caused by lightning

Fire caused by lightning is the event which is most likely to cause an environmental disturbance in a grassland biome.

Fire caused by lightning is the cause of environmental disturbance in a grassland biome because the fire can burn all the grassland vegetation which directly influence the organisms of that biome.

So we can conclude that fire caused by lightning is the event which is most likely to cause an environmental disturbance in a grassland biome.

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If you combine the results of this question with the results from question 3B, what do you know about the total pH change caused by adding the last 0. 1 mL of HNO3 it is now an acid.

A chemical that gives off hydrogen ions in water and forms salts by combining with certain metals. Acids have a sour taste and turn certain dyes red. Some acids made by the body, such as gastric acid, can help organs work the way they should. An example of an acid is hydrochloric acid.Nitric acid is a nitrogen oxoacid of formula HNO3 in which the nitrogen atom is bonded to a hydroxy group and by equivalent bonds to the remaining two oxygen atoms.

Nitric acid is made by reaction of nitrogen dioxide ( NO 2) with water. The net reaction is: 3 NO 2 + H 2O → 2 HNO 3 + NO. Normally, the nitric oxide produced by the reaction is reoxidized by the oxygen in air to produce additional nitrogen dioxide.

pH may be defined as a measure of free acidity. More precisely, pH is defined as the negative log of the hydrogen ion concentration. The range of pH extends from zero to 14. A pH value of 7 is neutral, because pure water has a pH value of exactly 7.

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Answer:

112 kelvin

Explanation:

Volume = 4.00L

no of moles = 0.297

Pressure = 0.910 atm

Temperature = ?

Given our R (Molar gas constant ) = 0.082

Given the following parameters , This question is based on IDEAL GAS LAW.

IDEAL GAS LAW = PV =nRT

\(PV = nRT\\Lets make T the subject of the formula\\T = \frac{PV}{nR} T = \frac{ 0.910 * 4.00}{0.397*0.082 }\\\\T = 3.64/0.032554\\T = 111.8142\\T = 112 Kelvin\\\)

Rocksalt Structure: No close-packed directions.

FCC Metal Structure: [111] family of close-packed directions.

BCC Metal Structure: [110] family of close-packed directions.

The rock salt structure has a face-centered cubic (FCC) arrangement of both cations and anions. In this structure, there are no close-packed directions because the ions are arranged in a simple cubic pattern. Consider the [100], [010], and [001] directions as the primary directions of the rock salt structure.

In an FCC metal structure, the close-packed directions are represented by the [111] family. The [111] direction is the densest and corresponds to the stacking of atoms along the body diagonal of the cube. The [111] family includes directions such as [111], [1-11], [11-1], [1-1-1], [-111], [-1-11], [-11-1], and [-1-1-1].

In a BCC metal structure, the close-packed directions are represented by the [110] family. The [110] direction is the densest and corresponds to the stacking of atoms along the cube edge diagonal. The [110] family includes directions such as [110], [1-10], [-110], and [-1-10].

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No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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Answer:

The mass of solid copper chloride used in each experiment=15 g

Explanation:

We are given that

Mass of copper chloride in solution=300g/dm3

Volume of solution used in each experiment=50 cm3

We have to find the mass of solid copper chloride used in each experiment.

\(1cm^3=0.001 dm^3\)

\(50cm^3=0.05 dm^3\)

1 dm3 contained solid copper chloride=300 g

0.05 dm3 contained solid copper chloride=\(300\times 0.05\)g

0.05 dm3 contained solid copper chloride=15 g

Hence, the mass of solid copper chloride used in each experiment=15 g

The mass of 8.83x10^23 formula units of iron oxide can be calculated using the molar mass of iron oxide.

The molar mass of iron oxide is 159.69 g/mol.

Therefore, the mass of 8.83x10^23 formula units of iron oxide can be calculated by multiplying the molar mass by the number of formula units: Mass = 8.83x10^23  formula units x 159.69 g/mol Mass = 1.41x10^26 g

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Water different from most substances during phase changes because water changes into gaseous water or steam

Those portion of a system that are physically distinct and mechanically separable from other portion of the system are called phases and a phase change is occurring the liquid water is changing to gaseous water or steam and on molecular level the intermolecular forces between the water molecule are decreasing the heat is providing enough energy for the water molecule to overcome these attractive forces

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Answer:

 In the presence of heat, sodium bicarbonate, NaHCO3, decomposes to produce carbon dioxide, CO2, which results in the balanced reaction of 2 NaHCO3(s) + Na2CO3(s) + H2O(l) + CO2(g). In addition to its many uses, sodium bicarbonate can be utilized as a leavening agent while making doughnuts and quick bread, for example.

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Answer

Provide the body with the calories, or energy, to grow as well.

Answer:

Okay well simply drop it from one inch on to the ground and it won't break and you could put it into a basket with bubble wrap.

Explanation:

Well if you wrap the egg into bubble wrap a few times them put it into a basket (its your choice) then it won't break because the bubble wrap will just pop a few times but sometimes it depends on where you are dropping it from.

Have a blessed day bye! ;)

Since the ethanol has a density of 0.800 g/mL, the mass of the ethanol is 180 grams.

Given the following data:

Volume of ethanol = 225 mL

Density of lead ball = 0.800 g/mL.

To find the mass of the ethanol;

Density can be defined as mass all over the volume of an object.

Mathematically, the density of a substance is given by the formula;

Density = Mass/Volume

Making mass the subject of formula, we have;

Mass = Density x Volume

Substituting the given parameters into the formula, we have;

Mass of ethanol = 180 grams.

Answer: The answer is C

covalent bonds have a lower melting and boiling point

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