What is the acceleration of a Porsche that can go from 15 mi/hr to 75 mi/hr in 4 seconds?
G: 15 mi/hr 75 mi/hr 4 seconds
U:
E:
S:

Answer:

The direction of defliection of the site to the left I think ..

Both the ships will see the other ship with the same velocity i.e, 0.999c m/s.

To calculate the velocity of one ship as seen by the other ship, we need to use the velocity transformation formula derived from Lorentz transformation:

V = {v1 - v2/1-(v1)(v2)} x c

Here v1 and v2 are the velocities of the two ships

As the ships are heading towards each other v1 = -v2 = 0.999c

Putting this value in the above equation

V = 0.999c + 0.999c/1 - (0.999c)(0.999c) x c = 0.999c m/s

Hence, both the ships will see the other ship with the same velocity i.e, 0.999c m/s.

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The Spring constant of the trampoline when a branch of mass 0.35 kg falls on it is 910 N/m.

Spring constant is the as force constant, and it is defined as the ratio of the force to extension of an elastic material.

To calculate the spring constant of the trampoline, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the spring constant of the trapoline is 910 N/m.

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Answer:2.67

Explanation:

Nun

The authors of the simulation made scaling choices so that the tidal distortion effect from the moon on Earth could actually be seen and appreciated.

The simulation was designed to demonstrate the tidal distortion effect, which is the result of gravitational forces between theEarthh and the moon. The effect causes the tides to rise and fall in a predictable pattern. In order for this effect to be visible in the simulation, the authors needed to scale the earth and moon appropriately.

The scaling choices in the simulation were made with a specific purpose in mind, which was to illustrate the tidal distortion effect between the Earth and the moon. By scaling the objects in the simulation appropriately, the authors were able to achieve this goal and provide a clear visualization of this phenomenon.

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Jupiter is a gas giant and one of the largest planets in our solar system. It has a strong gravitational field and intense magnetic fields, which cause it to release enormous amounts of energy. True

This energy is generated by the planet's internal heat, caused by the gravitational pull of Jupiter's enormous mass on its own gases. In fact, Jupiter releases almost twice as much energy into space as it receives from the Sun.

This energy is mostly in the form of radiation, including infrared, ultraviolet, and radio waves. Scientists are still studying the complex processes that generate this energy, but it is clear that Jupiter is a very active and dynamic planet, with a lot to teach us about the workings of our solar system.

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Answer:

a kinetic energy

Explanation:

because it is moving

Answer:

negative or posotive i think

Explanation:

The piston the student is standing on has a 0.22-times larger diameter than the piston the elephant stands on.

Given parameters:

Mass of the student: m = 70 kg.

Mass of the elephant: M = 1200 kg.

Let the diameters of the piston the student is standing on and the piston the elephant is standing on are respectively d and D.

Using Pascal's law , we can write,

Force applied by the student's weight  ÷ area  of the piston the student is standing on = Force applied by the elephant's weight ÷ area  of the piston the elephant is standing on.

⇒ 70 kg × g / π d² = 1200 kg × g / π D²

⇒ 1400 d² = 70 D²

⇒ d= 0.22D.

Hence, The piston the student is standing on has a diameter that is 0.22 times larger than the piston the elephant is standing on.

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Answer:

time taken = 7.514 seconds

\(\sf{acceleration} = \dfrac{\Delta v}{\Delta t} = \dfrac{final \ speed - initial \ speed}{time \ taken}\)

Here given:

using the given formula:

\(\hookrightarrow \sf{1.77} = \dfrac{24.4 - 11.1}{time \ taken}\)

\(\hookrightarrow \sf{time \ taken} = \dfrac{24.4 - 11.1}{1.77}\)

\(\hookrightarrow \sf{time \ taken} = 7.514 \ seconds\)

Formula :

\( \frac{final \: speed - initial \: speed}{time \: taken} \)

Given :

Solution :

\(1.77 = \frac{24.4 - 11.1}{time \: taken} \)

\(time \: taken = \frac{24.4 - 11.1}{1.77} \)

\(taken \: time = 7.514 \: seconds\)

The average distance between Mars and Earth is about 140 million miles (225 million kilometers).

This distance varies depending on their respective positions in their orbits around the Sun. This can range from about 34 million miles (55 million kilometers) when the planets are at their closest approach, to over 250 million miles (400 million kilometers) when they are at their farthest point in the orbit. This distance can impact the feasibility and duration of interplanetary missions, such as the recent Mars rover missions, which take advantage of the most efficient trajectory to minimize travel time and distance. Understanding and measuring the distance between Mars and Earth is important for many scientific and exploration purposes, such as studying the Martian atmosphere and geology, and planning for future human missions to the Red Planet.

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The average speed of P-waves in the Earth's crust is around 6 km/s, so the time taken by P-waves to travel a distance of 6 meters is 0.001 seconds.

P-waves, also known as primary waves or pressure waves, are a type of seismic wave that travels through the Earth's interior during an earthquake. They are the fastest seismic waves and the first waves to be detected by seismic instruments. P-waves are longitudinal waves.

The average speed of P-waves in the Earth's crust is around 6 km/s, but they can travel up to 13 km/s through the Earth's core.

To calculate the time taken by P-waves to travel 6 meters, the formula below is used:

Time taken = distance/speed

distance = 6.0 m or 0.006 km; speed = 6.0 km/s

Time taken =  0.006/6

Time taken = 0.001 seconds

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Answer:

Sorry I need points \( \boxed{}\)

It states that the force F acting on a body is equal to the mass m of the body multiplied by the acceleration an of its center of mass, or F = ma.

The fundamental equation of motion in classical mechanics is F = ma.

Since gravity affects an object's vertical motion, while it moves, it is said to be in motion under gravity.

The force that pushes objects downward is called gravity. In reality, gravity draws things toward the centre of the Earth. Homogeneous acceleration is experienced by a body in free fall.

Motion. It is said that the body is moving at an accelerated rate. Therefore, if a body falls freely while being affected by gravity, its velocity will begin to increase at a rate of 9.8 m/s2.

When a body falls freely under the effect of gravity alone in a vacuum, potential energy continuously decreases and kinetic energy continuously increases; as a result, the conservative force acts on the body.

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Answer:

avoid verbal argument and walk away

Answer:

What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.

Explanation:

What happens to the density of an object if the object is cut in half? ... The density remains the same because cutting the object in half will divide the mass & volume by the same amount. Also, the density of a substance remains the same no matter what size it is.

Answer:

B. What are the base units of electric current?

To find out that the electric current is a vector or scalar quantity, Tim should ask what is the symbol for electric current. Hence, option C is correct.

A physical quantity whose size is a complete description of it. Volume, density, speed, energy, mass, and time are a few examples of scalars. Other quantities, like as force and velocity, are referred to as vectors since they have both magnitude and direction.

Real numbers that are typically positive but not always characterize scalars.

In physics, a vector is a quantity with both magnitude and direction. It is often represented by an arrow whose length is proportional to the magnitude of the quantity and whose direction is the same as that of the quantity. A vector does not have position, while having magnitude and direction. In other words, a vector's shape is unaltered if it is shifted parallel to itself as long as its length is unaltered.

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The total resistance and current flowing through the circuit is equal to 60 Ohms and 2 Amperes respectively.

Given the following data:

Resistors = 20 Ohms.

Voltage = 120 Volts.

Since the three resistors are connected in series, we would calculate their total resistance by adding them up as follows:

RT = R1 + R2 + R3

RT = 20 + 20 + 20

RT = 60 Ohms.

Next, we would determine the current that is flowing through the circuit by applying Ohm's law.

From Ohm's law, we have:

V = IR

I = V/R

I = 120/60

I = 2 Amperes.

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Answer:

Average speed is the total distance traveled divided by the time. Speed takes into account the total path length traveled. Average velocity is the displacement divided by the time. Velocity only takes into account the starting and ending points of an object's path.

Explanation:

Answer:

2.205 pounds

Explanation:

5.5 kg is 2.205 lbs. hope this helps!

Kinetic energy the earth possess due to this orbital motion is 13242.55 × 10³⁰ kg.mph²

Kinetic energy, the form of energy that a body or particle has due to its motion. work done on an object by applying a net force transfers energy and the object accelerates, thereby gaining kinetic energy. Kinetic energy is a property of a moving object or particle that depends not only on its motion but also on its mass. The type of movement can be translation (or movement along a path from one place to another), rotation about an axis, oscillation, or any combination of movement.

The translational kinetic energy of a body is equal to half the product of the square of its mass m and its velocity v, or 1/2mv²

For the given question:

Kinetic energy: \(\frac{1}{2}\) mv²

Given,

Mass of earth: 5.9722×10²⁴ kg

Tangential speed of earth: 67,000 mph

So, Kinetic energy: \(\frac{5.9722*10^{24}*67,000^{2} }{2}\)

= 26485.1 × 10³⁰/2

= 13242.55× 10³⁰ kg.(mph)²

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Answer:

4000 J

Explanation:

KE = (1/2)(m)(v^2)

KE = .5*500*(4^2)

KE = 4000 J

Answer:

Smoke detectors

Explanation:

This is because the ionization chamber in smoke detectors uses radiation, a form of heat transfer to detect smoke.

.The NRC allows beneficial use of smoke detectors which is a radioactive material because a smoke detector has the ability to save lives . it's ability to save lives outweighs any health risk from the radiation. The smoke detector use a very minimal amounts of radioactive materials.

Answer: The household item which uses radiation in a beneficial way is the SMOKE DETECTORS

Explanation:

Radiation is a type of energy that has the ability to travel through space and penetrate materials. There are various types of radiation which include alpha, beta and gamma rays. Many uses of radiation help to ensure high quality and safety of our daily lives. A typical example is seen in smoke detectors.

Smoke detectors are devices installed in a building which serves the purpose of detecting smoke which usually is associated with fire and sounding off an alarm. The types of smoke detectors available depends on their mode of action and these include:

--> Ionization smoke detectors: These type of detector are generally more sensitive to flamming fires. They have an in built small amount of RADIOACTIVE material between two electrically charged plates, which ionizes the air and causes current to flow between the plates. When smoke enters the chamber, it disrupts the flow of ions, thus reducing the flow of current and activating the alarm. An isotope of americium which emits alpha particles is used in this type of smoke detectors and it's an example of an alpha radiation.

Therefore, the household item which uses radiation in a beneficial way is the SMOKE DETECTORS.

To determine the total mechanical energy of the block-ramp-Earth system for all trials, the student needs to use the conservation of mechanical energy principle.

According to this principle, the total mechanical energy of a system remains constant when there is no external work done on it. In this case, the system comprises the block, ramp, and Earth. The initial mechanical energy of the system is the sum of the kinetic energy of the block at point A and the potential energy due to its height above the ground. At point B, the final mechanical energy of the system is the potential energy due to the height of the block above the ground.
The student should first calculate the initial and final potential energy of the block at point A and point B, respectively. Then, they should calculate the initial kinetic energy of the block at point A using the given value of v0. Next, they should calculate the final kinetic energy of the block at point B, which is zero as the block comes to rest.

Finally, they can use the conservation of mechanical energy principle to equate the initial and final mechanical energy of the system for each trial and solve for the unknown quantities. The frictional force acting on the block during each trial can be calculated using the known quantities and included in the calculations.

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The time required to cover the Moon to a depth of 1.20 meters with micrometeorites.

To find out how long it would take to cover the Moon to a depth of 1.20 meters with micrometeorites, we can calculate the volume of the Moon and then divide it by the volume of one micrometeorite. Let's break down the calculation step by step:

Calculate the volume of the Moon:

The average radius of the Moon is approximately 1.737 ×10⁶ meters. Using the formula for the volume of a sphere, V = (4÷3)πr³, we can calculate the volume of the Moon.

\(V_{moon}\) = (4÷3)π(1.737 × 10⁶)³

Calculate the volume of one micrometeorite:

The diameter of the micrometeorite is given as 1.30 ×10⁽⁻⁶⁾ meters, which means the radius is half of that.

\(r_{meteorite}\) = (1.30 × 10⁽⁻⁶⁾)÷2

Using the formula for the volume of a sphere, V = (4÷3)πr₃, we can calculate the volume of one micrometeorite.

\(V_{meteorite}\) = (4÷3)π((1.30 × 10⁽⁻⁶⁾)÷2)³

Calculate the number of micrometeorites needed to fill the Moon:

To find the number of micrometeorites required to fill the Moon, we divide the volume of the Moon by the volume of one micrometeorite.

\(N_{meteorites}\) = \(V_{moon}\) ÷ \(V_{meteorite}\)

Calculate the time to fill the Moon:

Since one micrometeorite strikes each square meter of the Moon each second, we can equate the number of micrometeorites needed to fill the Moon to the number of seconds it would take.

Time = \(N_{meteorites}\) ÷ (1 m²/s)

Convert seconds to years:

Finally, we convert the time in seconds to years by dividing by the number of seconds in a year (assuming 365.25 days in a year and 24 hours in a day).

\(Time_{years}\) = Time ÷ (365.25 days/year × 24 hours/day × 3600 seconds/hour)

Performing these calculations will give us the time required to cover the Moon to a depth of 1.20 meters with micrometeorites.

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The final speed of both playdoughs which stick together after the collision is 0.5 m/s

The mass of the first playdough = 0.5 kg

The mass of the second playdough = 0.25 kg

The initial speed of the first playdough =  1.5 m/s

The initial speed of the second playdough = 2 m/s

The final speed of both playdoughs can be found using the formula,

       m₁u₁ + m₂u₂ = (m₁ + m₂) v

where m₁,m₂ is the mass of the first and second playdough respectively

           u₁,u₂ is the initial speed of the first and second playdough respectively

           v is the final speed of both playdough

Let us substitute the known values in the above equation, we get

          0.5 x 1.5 + 0.25 x 2 = (0.5 + 0.25) v

                         0.75 x 0.5 = 0.75v

                                  0.375 = 0.75v

                                         v = 0.375 / 0.75

                                            = 0.5 m/s

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P(white) = 27/100 = 270/1000

Therefore, in 1,000 pulls, we eaxpect 270 white beads,

Answer:

Wtens = (20 N) * (5 m) * cos (0 deg) = +100 Joules

Wgrav = (20 N) * (5 m) * cos (180 deg) = -100 Joules

Wapp= (10 N) * (5 m) *cos (0 degrees) = +50 Joules

Wfrict =(10 N) * (5 m) * cos (180 degrees) = -50 Joules

Wapp = (10 N) * (5 m) * cos (0 deg) = +50 Joules

Wfrict = (10 N) * (5 m) * cos (180 deg) = -50 Joules

Explanation:

Apply the work equation to determine the amount of work done by the applied force in each of the three situations described below.