Find the side legnth of a square with an area of 242m ^2.

Answer:

slope = - \(\frac{3}{11}\)

Step-by-step explanation:

Calculate the slope m using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (- 5, 7) and (x₂, y₂ ) = (6, 4)

m = \(\frac{4-7}{6+5}\) = \(\frac{-3}{11}\) = - \(\frac{3}{11}\)

Answer:

165 students or the sophomore class of 220 are not athletic.

Step-by-step explanation:

60/240 = .25 This means that 25% of the class is athletic.  That would mean and .75 or 75% are not athletic.

220 x .75 = 165

each driver travels both routes at different times, and the travel times for each driver on each route are recorded. In this way, we can achieve a more effective comparison of the routes.

a) Factor or factors within this study are the Routes (A and B). The levels of the factors are the corresponding drivers assigned to each of the routes. Treatments being compared are the routes (A and B).b) To test the hypothesis statistics corresponding we need to perform ANOVA.One-way ANOVA: Analysis of Variance between two groupsNull Hypothesis: H0:μ1=μ2Alternative Hypothesis: H1:μ1≠μ2Significance level: α = 0.05Degree of freedom: df = 2 + 5 + 5 – 1 = 11Critical value = 3.82Decision rule: Reject the null hypothesis if the test statistic F is greater than the critical value F0.05,1,8 = 5.317.So, we can calculate ANOVA table using Minitab:ANOVA: Single Factor  Sum of Squares  df  Mean Square  F  PValue Factor  146.00  1  146.00  5.12  0.049 Error  406.00  8  50.75       Total  552.00  9Test statistic F = 5.12 < 5.317, so do not reject the null hypothesis.c) We can create the following simultaneous box plot to determine which route is better:The box plot shows that Route A has less travel time on average than Route B, so Route A is better.d) Another way to obtain the data can be: We can assign each driver to both Routes (A and B). ,

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a) The factor being studied in this scenario is the route chosen for carrying the merchandise.

b) There is a significant difference between the mean travel times for Route A and Route B.

c) Its indicating that Route A is the better option.

d) For controlling external factors such as weather and traffic conditions would also provide more accurate and precise results.

Given that,

The data obtained were:

Travel time

Route A 18 24 30 21 32

Route B 22 29 34 25 35

a) The factor being studied in this scenario is the route chosen for carrying the merchandise.

And, The levels of the factor are Route A and Route B.

And, The treatments being compared are the travel times for each route, which were collected and compared between the two groups of drivers assigned to each route.

b) For test whether there are significant differences between the routes, we will perform a two-sample t-test.

The null hypothesis states that there is no difference in the mean travel time between Route A and Route B.

The alternative hypothesis states that there is a significant difference in the mean travel time between Route A and Route B.

Hence, We can calculate the sample means and standard deviations for each group:

Route A mean = (18+24+30+21+32)/5 = 25

Route B mean = (22+29+34+25+35)/5 = 29

Route A standard deviation = 5.3

Route B standard deviation = 5.1

Hence, Using a 95% confidence level, and a two-sided test, with 8 degrees of freedom, we find a t-value of 2.306.

So, The calculated t-value (t = -2.56) is greater than the t-value we found, so we can reject the null hypothesis and conclude that there is a significant difference between the mean travel times for Route A and Route B.

c) Since we have rejected the null hypothesis, we can now create simultaneous box plots to determine which route is better.

From the box plots, Route A has a lower median travel time and a narrower interquartile range,

Hence, Its indicating that Route A is the better option.

d) An alternative design to obtain more effective comparison data would be to randomly assign drivers to either Route A or Route B on a daily basis, and then record the travel time for each driver over a set period of time.

This would allow for a larger sample size and more accurate representation of the average travel time for each route.

Additionally, controlling for external factors such as weather and traffic conditions would also provide more accurate and precise results.

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Answer:

B. 4x+5

Step-by-step explanation:

First, you multiply both sides by 4, then you have x=y-5. You then add 5 to get 4x+5

(in the very beginning, you switch the x and y so you would have to make the equation x= y-5 / 4 if that confused you)

\(\frac{2}{x}\)

\(\frac{x}{2}\)

\(\frac{4x^4}{y^3}\)

a. 2x^-3 • 4x^2

To solve this using only positive exponents, follow these steps:

i. Rewrite the expression in a clearer form

2x⁻³ . 4x²

ii. The position of the term with negative exponent is changed from denominator to numerator or numerator to denominator depending on its initial position. If it is at the numerator, it is moved to the denominator. If otherwise it is at the denominator, it is moved to the numerator. When this is done, the negative exponent is changed to positive.

In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

\(\frac{1}{2x^3} . 4x^2\)

iii. We then solve the result as follows;

\(\frac{1}{2x^3} . 4x^2\) = \(\frac{2}{x}\)

Therefore, 2x⁻³ . 4x² = \(\frac{2}{x}\)

b. 2x^4 • 4x^-3

i. Rewrite as follows;

2x⁴ . 4x⁻³

ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

\(2x^4 . \frac{1}{4x^3}\)

iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

\(\frac{x}{2}\)

Therefore, 2x⁴ . 4x⁻³ = \(\frac{x}{2}\)

c. 2x^3y^-3 • 2x

i. Rewrite as follows;

2x³y⁻³ . 2x

ii. Change position of terms with negative exponents;

\(2x^3.\frac{1}{y^3} .2x\)

iii. Now solve;

\(\frac{4x^4}{y^3}\)

Therefore, 2x³y⁻³ . 2x = \(\frac{4x^4}{y^3}\)

Answer:

Not sure if this will help but that looks like a bisection of angles BAC and TSR.

Answer:

4(x+3)

Step-by-step explanation:

\(\frac{8(x+3)^{2} }{2(x+3)} =4(x+3)^{2-1} =4(x+3)\)

I hope this help you

ayoooo n = 0

40 + (0) = 40

Answer:

n=0

Step-by-step explanation:

Flip the equation and subtract 40 from both sides

40=40+n

n+40=40

n+40-40=40-40

n=0

Answer:

\(p=20c^{2} +7c-6\)

Step-by-step explanation:

\(p=5c^{2} +15c^{2} +8c+c-2c+6-9-3\)

\(p=20c^{2} +7c-6\)

Hope this helps

The equation that could represent a linear combination of the system 2/3x + 5/2y = 15 and 4x + 15y = 12 is 0 = 26

Linear equations are equations that have constant average rates of change, slope or gradient

A system of linear equations is a collection of at least two linear equations.

In this case, the system of equations is given as

2/3x + 5/2y = 15

4x + 15y = 12

Multiply the first equation by 6, to eliminate the fractions.

6 * (2/3x + 5/2y = 15)

This gives

4x + 15y = 90

Subtract the equation 4x + 15y = 90 from 4x + 15y = 12

4x - 4x + 15y - 15y = 12 - 90

Evaluate the difference

0 + 0 = -78

Evaluate the sum

0 = -78

The above equation is the same equation as option (b) 0 = 26

This is so because they both represent that the system of equations have no solution

Hence, the equation that could represent a linear combination of the system is 0 = 26

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Complete question

The system of equations below has no solution.

2/3x + 5/2y = 15

4x + 15y = 12

Which equation could represent a linear combination of the system?

The speed of the aeroplane per hour during the journey is (d) 1550 km/hr.

The time the aeroplane would take to reach its destination if it starts on schedule is T.The distance from the starting point to its destination is D.The speed of the plane from the starting point to its destination is S.When the plane starts 1.5 hours late, it takes T + 1.5 hours to reach its destination at the scheduled time.The distance traveled by the plane under this circumstance is still D.

When the pilot increases the speed of the plane by 800 km/h, the time it takes to travel from the starting point to the destination is reduced by 1.5 hours. So, the time taken to travel the distance D is (T - 1.5) hours.The formula to find speed is distance divided by time.Using these values we can find the speed of the aeroplane.

Solving the equation,D/S = T... equation [1]D/S+800 = T - 1.5... equation [2]Substitute the value of T from equation [1] in equation [2], we get:D/S + 800 = D/(S + 800) - 1.5Solving the equation, we get:S2 - 400S - 3,20,000 = 0S = 1550 km/hr

Therefore, the speed of the aeroplane per hour during the journey is (d) 1550 km/hr.

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If Tiffany had invested her $5,000 in stocks instead of keeping it in a bank account, there would be several differences in terms of potential returns, risks, and liquidity.

Firstly, investing in stocks has the potential to generate higher returns compared to a bank account. The stock market has historically yielded an average return of 10%, while the interest rates on savings accounts are much lower, typically around 0.01%-0.05%. Therefore, if Tiffany had invested her $5,000 in stocks, she could have potentially earned higher returns over time.

In conclusion, investing in stocks instead of keeping money in a bank account can potentially lead to higher returns, but also comes with greater risks and less liquidity. It ultimately depends on Tiffany's personal financial goals, risk tolerance, and time horizon for investing.

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Answer:

x^2 + 14x + 57 = 0

Step-by-step explanation:

(x+5)^2+4(x+5)+12 = 0

x^2 +10x + 25 + 4x + 20 + 12 = 0

x^2 + 14x + 57 = 0

Answer:

GCF of 3 and 6 is 3.

LCM of 3 and 6 is 6.

Step-by-step explanation:

Answer:

Step-by-step explanation:

A rational number is one that can be expressed as a fraction. Pi cannot be. If I tell you that the 2000th digit of pi is an 8 (which it probably isn't) and I ask you to tell me the 2001 value of pi, you have no better odds that 1/10 of getting it right.

A rational number can always be reduced to a fraction. 20 1/2 can be expressed as a fraction. It is 20.5

Pi is irrational. I don't know the value of pi beyond what a calculator can tell me.  3.14159265 The next digit is a 4. I know this only because that is what the calculator tells me.

Repeating decimals call always be represented as a fraction. For ex

x = 0.123123123123123

1000x = 123.123123123123

       x =       .123123123123123      Subtract

999x = 123

This comes about because in both cases what is after the decimal is the same.

x = 123/999 = 41/333

Answer:

$62.05 is the new price

the reduced price is $10.95

Step-by-step explanation:

73*.85=62.05

Answer:

Where the heck is the question my dude

Step-by-step explanation:

:)

Answer: 5

Step-by-step explanation:

Answer:

15

Step-by-step explanation:

15= 3*5, so not prime

Answer:

Step-by-step explanation:

See image

Step-by-step explanation:

13) 4x-22+x+11+10x-4 =180

15x=195

x=13

<P=(10(13)-4)=126

<Q=(4(13)-22)=30

<R=13+11=24

Answer:

so what is the question ??

Answer:

$42.80    check

   x.20     tip

 $8.56

Then add the the total check $42.80 +$8.56 = $51.36 John will spend

Step-by-step explanation:

to find the tip multiply the total by the tip

if 10%  x it by .10

if 16%  x it by .16

if 25 % x it by.25 and so on then add that to the total of the bill

Answer:

See below.

Step-by-step explanation:

Divide to turn the percentage into decimal form.

\(\frac{20}{100} =.20\)

Multiply the percentage by the amount.

\(42.80*.20=8.56\)

Add them together.

\(42.80+8.56=51.36\)

Answer: \(51.36\)

:)

Answer:

4/12 is equal to 3/9

Step-by-step explanation:

least common denominator for 12 and 9

36

4/12=12/36

3/9=12/36

Answer:

55

Step-by-step explanation:

if it cost 2,145 for the whole thing and 39 for each person 2,145 divide by 39= 55

Answer:

-To find the cost of one gallon of gas in Toronto, you have to multiply the cost of one liter of gasoline for 3.8 as you know that there are 3.8 liters in one gallon:

$0.91*3.8=$3.46

This means that a gallon of gas cost $3.46 in Toronto.

-$3.46-$2.29=$1.17

Considering that one gallon of gasoline cost $2.29 in Buffalo and $3.46 in Toronto, the cost is greater in Buffalo. The cost is greater by $1.17.

During his shift at Speedy Eats taco truck, Dan tracked the number of toppings each customer ordered. In his record sheet, Dan created a column to note down the taco toppings ordered by each customer.

Dan's record sheet also had an empty column, which could be used for any additional information related to the toppings or the customers. This empty column could be utilized by Dan to record special requests or preferences made by the customers, or any other relevant details that might be useful for future reference.

Moreover, Dan also added an interactive column in his record sheet. This interactive column could be used to note down any feedback or comments given by the customers regarding the toppings or the overall experience at Speedy Eats taco truck. It would allow Dan to understand the customers' preferences better and make necessary improvements if needed.

In conclusion, Dan's record sheet included a column for taco toppings, an empty column for additional information, and an interactive column for customer feedback. These columns provided Dan with a comprehensive way to track the number of toppings, gather customer preferences, and make informed decisions to enhance the taco truck's offerings and customer experience.

During his shift at Speedy Eats taco truck, Dan used three different columns in his record sheet to track the number of toppings each customer ordered. These included a column for taco toppings, an empty column for additional information, and an interactive column for customer feedback. This system allowed Dan to keep a detailed record of the toppings chosen by customers, note down any special requests or preferences, and gather valuable feedback to enhance the taco truck's offerings and overall customer experience.

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