Give an example of each element,compound, and mixture

Answer:

1) Assuming an adult person has an average mass of m=80 kg, and assuming it takes about 30 seconds to climb 5 meters of stairs, the energy used by the person is

So the power output is

And since the estimate we made is very rough, we can say that the power output of the person is comparable to the power output of the light bulb of 100 W.

2) Based on the results we found in the previous part of the exercise, since the power output of the person is comparable to the power output of 1 light bulb of 100 W, we can say that the person could have kept burning only one 100-W light bulb during the climb.

Explanation:

The car is moving at approximately 12.5 meters per second.

The kinetic energy (KE) of an object can be calculated using the formula:

KE = 1/2 * m * \(v^2\)

where

KE = kinetic energy,

m =Mass of the object, and

v = velocity.

In this case, we are given the mass (m) of the car as 1600 kg and the kinetic energy (KE) as 125,000 J. To find the velocity .

Substituting the  values , we have:

125,000 J = 1/2 * 1600 kg *\(v^2\)

Now, we can solve for v by rearranging the equation:

\(v^2\) = (2 * 125,000 J) / 1600 kg

\(v^2\) = 156.25 \(m^2/s^2\)

Taking the square root, we find:

v = √156.25\(m^2/s^2\)

v ≈ 12.5 m/s

Therefore, the car is moving at approximately 12.5 meters per second.

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Answer:

he fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion

Explanation:

The initial horizontal velocity of the bluefish is 0.45 m/s. When it begins tail motion, it experiences an additional force due to the thrust produced by the tail. The thrust produced by the tail is 0.65 N. We can use Newton's second law to find the acceleration produced by this force:

F = ma

0.65 N = 1.7 kg * a

a = 0.38 m/s^2

This acceleration will cause the velocity of the bluefish to increase over time. The distance the fish travels during this time can be calculated using the kinematic equation:

d = vit + 1/2 at^2

where d is the distance traveled, vi is the initial velocity, a is the acceleration, and t is the time. Since the fish is initially coasting horizontally, its initial vertical velocity is 0 m/s. Therefore, vi = 0.45 m/s. The time interval for which the fish is tail-motoring is not given, so let's assume it is 2 seconds:

d = (0.45 m/s)(2 s) + 1/2 (0.38 m/s^2)(2 s)^2

d = 1.78 meters

Therefore, the fish would travel a horizontal distance of 1.78 meters during the 2 seconds of tail motion.

The disorder that does not appear to describe Greta's possible condition is epilepsy. The correct answer is B.

While epilepsy is a neurological disorder that can cause seizures and other symptoms, it does not typically result in the physical challenges that Greta is experiencing, such as spasticity and the need for a variable-speed tape recorder.

Additionally, epilepsy does not necessarily affect an individual's ability to communicate using finger spelling or impact their hearing or vision. Therefore, while Greta may have epilepsy in addition to her other challenges, it is not directly related to the issues she is experiencing in Mr. Popanopoulous' class.

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Your question seems incomplete, but I suppose the question was:

"Greta is experiencing difficulty in Mr. Popanopoulous' class because she has different needs than many of the other students. Greta must use a variable-speed tape recorder to record the lessons, she often struggles with spasticity, and she frequently uses finger spelling as a method of communication. Which of the following disorders does NOT appear to describe Greta's possible condition?

A) Cerebral palsy

B) Epilepsy

C) Hearing impairment

D) Visual impairment"

The net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 0.200 m is 3.00 × 10^-25 N.

Point charge calculations.

We can use Coulomb's law to find the electric force exerted by each point charge on an electron at a given point on the x-axis, and then add the two forces vectorially to obtain the net electric force.

Coulomb's law states that the magnitude of the electric force F between two point charges q1 and q2 separated by a distance r is given by:

F = k |q1 q2| / r^2

where k is the Coulomb constant, k = 8.99 × 10^9 N m^2 / C^2, and |q1 q2| is the absolute value of the product of the charges.

At x = 0.200 m, the distance between the electron and the -4.00 nC charge at the origin is r1 = 0.200 m, and the distance between the electron and the -6.50 nC charge at x = 0.800 m is r2 = 0.600 m. The electric force exerted by the -4.00 nC charge on the electron is:

F1 = k |q1 qe| / r1^2

where qe is the charge of the electron, qe = -1.60 × 10^-19 C. Substituting the given values, we get:

F1 = (8.99 × 10^9 N m^2 / C^2) × |-4.00 nC| × |1.60 × 10^-19 C| / (0.200 m)^2

= 1.44 × 10^-24 N

The electric force exerted by the -6.50 nC charge on the electron is:

F2 = k |q2 qe| / r2^2

Substituting the given values, we get:

F2 = (8.99 × 10^9 N m^2 / C^2) × |-6.50 nC| × |1.60 × 10^-19 C| / (0.600 m)^2

= 1.08 × 10^-24 N

The direction of F1 is towards the -4.00 nC charge, and the direction of F2 is away from the -6.50 nC charge. Therefore, the net electric force is:

Fnet = F1 + F2 = (1.44 - 1.08) × 10^-24 N = 0.36 × 10^-24 N

The direction of the net force is towards the -4.00 nC charge.

At x = 1.20 m, the distance between the electron and the -4.00 nC charge at the origin is r1 = 1.20 m, and the distance between the electron and the -6.50 nC charge at x = 0.800 m is r2 = 0.400 m. Following the same steps as before, we can calculate the electric forces exerted by each charge:

F1 = k |q1 qe| / r1^2

= (8.99 × 10^9 N m^2 / C^2) × |-4.00 nC| × |1.60 × 10^-19 C| / (1.20 m)^2

= 3.00 × 10^-25 N

F2 = k |q2 qe| / r2^2

= (8.99 × 10^9 N m^2 / C^2) × |-6.50 nC| × |1.60 × 10^-19 C

Therefore,  net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 0.200 m and  the net electric force that the two charges would exert on an electron placed at point on the x-axis at x = 1.20 m are 3.00 × 10^-25 N and (8.99 × 10^9 N m^2 / C^2) × |-6.50 nC| × |1.60 × 10^-19 C.

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Answer:

Approximately \(8.17\; \rm m \cdot s^{-1}\) assuming that the effect of gravity on the box can be ignored.

Explanation:

If the force \(F\) is constant, then the work would be found with \(W = F \cdot \Delta x\). However, this equation won't work for this question since the

\(\displaystyle W = \int\limits_{x_0}^{x_1} F\, d x\),

For this particular question, \(x_0 = 0\; \rm m\) and \(x_1 = 14.0\; \rm m\). Apply this equation:

\(\begin{aligned}W &= \int\limits_{x_0}^{x_1} F\, d x \\ &= \int\limits_{0\; \rm m}^{14.0\; \rm m} \left[{18.0\; \rm N} - {\left(0.530\; {\rm N \cdot m^{-1}}\right)}\cdot x \right]\, d x \\ &= \left[{(18.0\; \rm N)}\cdot x - \frac{1}{2}\;{\left(0.530\; {\rm N \cdot m^{-1}}\right)}\cdot x^2\right]_{x = 0\; \rm m}^{x = 14.0\; \rm m} \approx 200.06\; \rm N \cdot m\end{aligned}\).

(Side note: keep in mind that \(1\; \rm J = 1\; \rm N\cdot m\).)

Since friction is ignored, all these work should have been converted to the mechanical energy of this object.

Assume that the effect of gravity on this box can also be ignored. That way, there won't be a change in the gravitational potential energy of this object. Hence, all these extra mechanical energy would be in the form of the kinetic energy of this box.

That is:

\(\begin{aligned}& \text{Kinetic energy of this object} \\ =& \text{Initial Kinetic Energy} + \text{Change in Kinetic Energy} \\ =& \text{Initial Kinetic Energy} + \text{Change in Mechanical Energy} \\ =& \text{Initial Kinetic Energy} + \text{External Work} \\=& 0\; \rm N \cdot m + 200.06\; \rm N \cdot m \\ =& 200.06\; \rm N \cdot m \end{aligned}\).

Keep in mind that the kinetic energy of an object of mass \(m\) and speed \(v\) is:

\(\displaystyle \frac{1}{2}\, m \cdot v^{2}\).

Therefore:

\(\begin{aligned}v &= \sqrt{\frac{2\, (\text{Kinetic energy})}{m}} \\ &= \sqrt{\frac{2\times 200.06\; \rm N \cdot m}{6.00\; \rm kg}} \approx 8.17\; \rm m \cdot s^{-1}\end{aligned}\).

The boy throws the ball horizontally. The initial velocity of the ball as it left the boy's hand was approximately 3.72 m/s.

Initial velocity, often represented as v0, is the velocity of an object at the beginning of a time interval or at the start of a motion.

Use the following kinematic equations to arrive at the answer:

Horizontal velocity (Vx) = Distance / Time

Vertical displacement (y) = V0y*t + (1/2)gt²

Vertical velocity (Vy) = V0y + g*t

Tan(theta) = Vy / Vx

where V0y is the initial vertical velocity, g is acceleration due to gravity (9.8 m/s²), and theta is the angle of inclination.

First, let's find the time it takes for the ball to hit the ground. We can use the vertical displacement equation and set y = 0:

0 = V0y*t + (1/2)gt²

Simplifying and solving for t, we get:

t = sqrt((2y) / g)

= sqrt((21.10 m) / 9.8 m/s²)

= 0.472 s

Now, we can use the horizontal velocity equation to find Vx. Since the ball was thrown horizontally, Vx is the same as the initial velocity (V0):

Vx = Distance / Time

= (horizontal distance travelled by ball) / t

We don't know the horizontal distance travelled by the ball, but we can find it using the vertical displacement equation. At the instant the ball hits the ground, its vertical displacement (y) is:

y = V0y*t + (1/2)gt²

= 0 + (1/2)gt²

= (1/2)*9.8 m/s² * (0.472 s)²

= 1.10 m

This means the ball travelled a total distance of:

distance = horizontal distance + vertical distance

= x + 1.10 m

where x is the horizontal distance travelled by the ball. We can find x using the angle of inclination and the vertical displacement:

Tan(theta) = Vy / Vx

Vy = V0y + g*t

Solving for V0y, we get:

V0y = Vy - g*t

Plugging in the numbers, we get:

V0y = Tan(theta) * Vx - g*t

= Tan(30 deg) * Vx - 9.8 m/s² * 0.472 s

= 0.577 * Vx - 4.62 m/s

Now, we can use the vertical displacement equation again to find x:

y = V0yt + (1/2)gt²

= (0.577Vx - 4.62 m/s) * 0.472 s + (1/2)*9.8 m/s² * (0.472 s)²

= 1.10 m

Simplifying and solving for Vx, we get:

Vx = (2y - 0.577V0t) / t

= (21.10 m - 0.577*(0.577*Vx - 4.62 m/s)*0.472 s) / 0.472 s

= 3.72 m/s

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Option A) 3.9 km is the correct answer. the magnitude of Rhea's displacement vector is approximately 3.92 km.

In order to find out the magnitude of Rhea's displacement vector, we have to add up all of the displacement vectors.

Then we can use the Pythagorean theorem to calculate the magnitude of the resultant vector.

Since Rhea is first driving north for 2.4 km and then west for 3.1 km, we can represent her displacement vectors as follows: Δx = 0 km and Δy = 2.4 km for the first vector, and Δx = -3.1 km and Δy = 0 km for the second vector.

We can then add these vectors together by adding their components: Δx = 0 km + (-3.1 km) = -3.1 km and Δy = 2.4 km + 0 km = 2.4 km.

This gives us a resultant vector of -3.1 km east and 2.4 km north.

Using the Pythagorean theorem, we can find the magnitude of this vector: \(\sqrt{(\(-3.1 km)^{2} + (2.4 km)^{2} ) } = \sqrt{(9.61 + 5.76) km^{2} } = \sqrt{15.37 km^{2} } \approx 3.92 km.\)

Therefore, the magnitude of Rhea's displacement vector is approximately 3.92 km.

Therefore, option A) 3.9 km is the correct answer.

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The ray does not bend when it enters the semi circular glass block - Light ray incident on semicircular block at 90 degrees, therefore there is no change in the direction of ray at P.

Electromagnetic radiation that falls within the region of the electromagnetic spectrum that the human eye can see is known as light or visible light.

Light is electromagnetic radiation that the human eye can perceive. From radio waves with wavelengths measured in meters to gamma rays with wavelengths shorter than around 1 1011 meters, electromagnetic radiation occurs throughout an incredibly broad range of wavelengths.

Light governs our sleep-wake cycle and is crucial to our health and wellbeing. In actuality, "light" that is visible is a type of radiation, which is just energy that moves in the form of electromagnetic waves. It can alternatively be explained as a flow of "wave-packets," or particles, known as photons.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:The gravitational constant, denoted by the letter G, is an empirical physical constant involved in the calculation of gravitational effects in Sir Isaac Newton's law of universal gravitation and in Albert Einstein's general theory of relativity.

Hope this helps!! Brainlist plz?

Answer: B im sorry if its wrong

Explanation:

Answer: Matter is anything that is made of atoms and that has mass (A)

Explanation: All everyday objects that can be touched are ultimately composed of atoms. Even you are made of atoms. Anything that you can touch has moving particles unless the object is at absolute zero, which is not possible.

Hope this helps!

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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Temperature is most closely related to molecular Kinetic energy. Hence, option (A) is correct.

The kinetic theory of gases is a theory that can be used to deduce many of the gas's macroscopic features from a simplified molecular or particle description of the gas.

The most basic kinetic model is predicated on the following premises:

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Answer:

Explanation:

Ok so I don’t quite understand this

The aforementioned statement, "Measurements must be conducted carefully to ensure that all factors—aside from the variable—are the same,” is true. Controlling for all variables besides the variable of interest is crucial when performing scientific experiments or taking measurements.

By doing so, it is possible to make sure that any observed changes or impacts are caused by the variable being monitored and not by any confounding variables.

Researchers can isolate the effects of the particular variable they are examining by maintaining the status quo for all other factors. By keeping all other conditions constant, researchers can isolate the impact of the specific variable they are studying.

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Answer:

30m/s

Explanation:

Ya that's the right answer.

Answer:

a break in the circuit can also cause this problem

To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.

The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.

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From the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.

Matter is a substance made up of various types of particles that occupies physical space and has inertia.

A matter must have mass and occupy space.

Examples of matter include the following;

Thus, from the given list of items, examples of matter include, heat, air, water, gasoline, and bacteria.

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The frictional force of the wind on water produces surface currents that travel in a pattern analogous to "wind currents".

Wind, temperature, water density, and the moon's gravitational pull may all affect ocean currents.

Wind-driven waves, sometimes referred to as surface waves, are created by friction between the wind and the water's surface. When wind constantly disturbs the surface of an ocean or lake, a wave crest is created.

Friction slows the wind, which also changes its direction. This phenomenon might lead to surface roughness variations along regional boundaries or turbulence in winds near the surface. Turbulence stirs the lower atmosphere.

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The correct sequence is 5, 1, 3, 8, 4, 6, 7, 2. The statement that is being discussed is:

"For all > 0 there exists a > 0 such that for all satisfying we have that ."

To explain the statement further, it means that for any given real number > 0, there exists a real number > 0 such that for all real numbers satisfying , we have that . In other words, if is sufficiently close to (i.e. if is less than ), then must also be close to (i.e. must be less than ).

This idea is essential to understanding limits. The statement can be written more formally as:

\($$\lim_{x \to c} f(x) = L \iff \forall \epsilon > 0, \exists \delta > 0 \text{ such that } \forall x \in \mathbb{R}, 0 < |x - c| < \delta \Rightarrow |f(x) - L| < \epsilon$$\)

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sine's law

h/sin 30 = 50/sin 60

h/0.5 = 50/(0.5√3)

h=28.9 m

Answer:

because of gravity the ball falls

Answer:

Gravity

Explanation:

Gravity is the force the world gives which I magnetic and yeah-

Answer:

89 m

Explanation:

Applying

v = 2d/t................... Equation 1

Where v = velocity of sound in air, d = distance of the wall from Karen, t = time taken to hear the echo.

make d the subject of equation 1

d = vt/2..................... Equation 2

From the question,

Given: v = 343 m/s, t = 0.519 s

Substitute these values into equation 2

d = (343×0.519)/2

d = 89.01 m.

d ≈ 89 m

Answer:

Solution given:

Radius of small sphere[r]=5cm=0.05m

Radius of large sphere[R]=10cm=0.1m

capacitance of small sphere[c]=4πε0r

=\(4π*8.85×10^{-12}×0.05=5.56*10^{-12}F\)

Charge for small sphere[Q1]=100C

Charge for small sphere[Q2]=50C

Potential difference [V1]=\( \frac{charge}{capacitance}=\frac{100}{5.56*10^{-12}}=1.8×10^{13}\)V

.

again

capacitance of small sphere[C]=4πε0R

=\(4π*8.85×10^{-12}×0.1=1.11*10^{-11}F\)

Potential difference [V2]=\( \frac{charge}{capacitance}=\frac{50}{1.11*10^{-11}}=4.5×10^{12}\)V

Now

Loss of energy:

\( \frac{cC(V1-V2)^{2}}{2(c+C)}\)

=\( \frac{5.56*10^{-12}*1.11*10^{-11}(1.8*10^{13}-4.5*10^{12})^{2}}{2(5.56*10^{-12}+1.11*10^{-11})}\)

=25Joule