Jionne scores a 15/20 on her quiz. What percentage is this? (Hint: Convert the ratio to a decimal, then convert the decimal to a percent.)

Answer:

Distribute 1.2 to 6.3 and -7x

Combine 3.5 and 7.56

suhtract 11.06 from both sides

Answer:

the answer is A

Step-by-step explanation:

no explanation

The  standard deviation of the number of errors in students' statistics homework is 0.94

The percentage of students made three error = 13%

The percentage of students made two error = 27%

The percentage of students made one error = 40%

The percentage of students made zero error = 100 - (13+27+40)

= 100 - 80

= 20%

Next we have to find the value of E(x)

E(x) = 0.2(0) + 0.4(1) + 0.27(2) + 0.13(3)

= 0 + 0.4 + 0.54 + 0.39

= 1.33

Next find the value of variance

Variance = 0.2(0-1.33)^2 + 0.4(1-1.33)^2 + 0.27(2-1.33)^2 + 0.13(3-1.33)^2

= 0.35378 + 0.04356 + 0.121202 + 0.362557

= 0.8811

Standard deviation = \(\sqrt{0.8811}\)

= 0.94

Therefore, the standard deviation is 0.94

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Answer:

This is the Distributive Property.

The missing side of the right triangle has a length of 13.078.

In this problem we find a representation of a right triangle, where the length of a side and the measure of an angle are known. Trigonometric functions are trascendent functions that relates an angle and two sides of a right triangle. The trigonometric functions are listed below:

Sine

sin θ = y / r

Cosine

cos θ = x / r

Tangent

tan θ = y / x

Where:

If we know that y = 18 and θ = 54°, then the side adjacent to the angle is:

x = y / tan θ

x = 18 / tan 54°

x = 13.078

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Answer:

she can make 48 cookies.

Answer:

48

Step-by-step explanation:

If you divide 42 by 7 you get 6 so thats how many cookies she baked with one scoop. So then you add 6

The correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.

To calculate the probability of a cash flow being between $16,000 and $19,000, we can use the standard deviation and assume a normal distribution.

We are given that the average cash flow is $14,000 with a standard deviation of $5,000. These values are necessary to calculate the probability.

The probability of a cash flow falling within a certain range can be determined by converting the values to z-scores, which represent the number of standard deviations away from the mean.

First, we calculate the z-score for $16,000 using the formula: z = (x - μ) / σ, where x is the cash flow value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z1 = (16,000 - 14,000) / 5,000.

z1 = 2,000 / 5,000 = 0.4.

Next, we calculate the z-score for $19,000: z2 = (19,000 - 14,000) / 5,000.

z2 = 5,000 / 5,000 = 1.

Now that we have the z-scores, we can use a standard normal distribution table or calculator to find the corresponding probabilities.

Subtracting the probability corresponding to the lower z-score from the probability corresponding to the higher z-score will give us the probability of the cash flow falling between $16,000 and $19,000.

Looking up the z-scores in a standard normal distribution table or using a calculator, we find the probability for z1 is 0.6554 and the probability for z2 is 0.8413.

Therefore, the probability of the cash flow being between $16,000 and $19,000 is 0.8413 - 0.6554 = 0.1859, which is approximately 18.59%.

So, the correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.

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The probability of a cash flow between $16,000 and $19,000 is approximately 18.59%.

To calculate the probability of a cash flow being between $16,000 and $19,000, we can use the standard deviation and assume a normal distribution.

We are given that the average cash flow is $14,000 with a standard deviation of $5,000. These values are necessary to calculate the probability.

The probability of a cash flow falling within a certain range can be determined by converting the values to z-scores, which represent the number of standard deviations away from the mean.

First, we calculate the z-score for $16,000 using the formula: z = (x - μ) / σ, where x is the cash flow value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z1 = (16,000 - 14,000) / 5,000.

z1 = 2,000 / 5,000 = 0.4.

Next, we calculate the z-score for $19,000: z2 = (19,000 - 14,000) / 5,000.

z2 = 5,000 / 5,000 = 1.

Now that we have the z-scores, we can use a standard normal distribution table or calculator to find the corresponding probabilities.

Subtracting the probability corresponding to the lower z-score from the probability corresponding to the higher z-score will give us the probability of the cash flow falling between $16,000 and $19,000.

Looking up the z-scores in a standard normal distribution table or using a calculator, we find the probability for z1 is 0.6554 and the probability for z2 is 0.8413.

Therefore, the probability of the cash flow being between $16,000 and $19,000 is 0.8413 - 0.6554 = 0.1859, which is approximately 18.59%.

So, the correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.

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The surface area of the given prism is 484 cm². A prism is a three-dimensional object that has two parallel congruent bases and rectangular sides connecting these bases.

To find the surface area of a prism, we need to add up the areas of all its faces.

In this case, we are given the dimensions of the prism as follows:
- The length of one base is 12 cm
- The width of one base is 5 cm
- The height of the prism (distance between the bases) is 13 cm
- The length of each rectangular side is 7 cm

To start finding the surface area, we can begin by calculating the area of each face of the prism. The two bases are congruent rectangles, so each has an area of:

Area of one base = length x width
Area of one base = 12 cm x 5 cm
Area of one base = 60 cm²

Since there are two bases, we can multiply this by 2 to get the total area of both bases:

Total area of both bases = 2 x 60 cm²
Total area of both bases = 120 cm²

Next, we need to calculate the area of each of the four rectangular sides of the prism. Each of these is a rectangle with length 7 cm and height 13 cm. So, the area of one side is:

Area of one side = length x height
Area of one side = 7 cm x 13 cm
Area of one side = 91 cm²

Since there are four sides, we can multiply this by 4 to get the total area of all four sides:

Total area of all four sides = 4 x 91 cm²
Total area of all four sides = 364 cm²

Finally, to get the total surface area of the prism, we need to add together the areas of both bases and all four sides:

Total surface area of the prism = area of both bases + area of all four sides
Total surface area of the prism = 120 cm² + 364 cm²
Total surface area of the prism = 484 cm²

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Answer:

29

Step-by-step explanation:

5x5=25

25+4=29

First for 5 times 5 u do 5x5=25 and for (5x5) plus four u add 4 to the answer of 5 times five which makes 29.

Answer:

The answer is 29

Step-by-step explanation:

5 times 5 plus 4

5 × 5 + 4

Use BODMAS

(Bracket of Division, Multiplication, Addition and Subtraction)

(5 × 5) + 4 = 25 + 4 = 29

Thus, The answer is 29

-TheUnknownScientist 72

Management of the Canine Gourmet Company wants the box-filling line to be set so that the process average weight per packet is **X grams**. To ensure that the process is in control, an inspector at the end of the filling line periodically selects a random box of packets and weighs each packet. When the process is in control, the range in the weight of each sample has averaged **Y grams**.

To maintain control over the filling line process and achieve the desired average weight per packet, several steps can be taken. First, it is essential to establish a target weight for each packet, which in this case is **X grams**. This target weight ensures consistency and meets the expectations of the discriminating canine customers.

To monitor the process and ensure it remains in control, the inspector randomly selects boxes of packets and weighs each individual packet. By calculating the range of weights within each sample, the inspector can determine the variability of the weights. In this case, the average range of **Y grams** is used as a benchmark to assess whether the process is within acceptable limits.

Maintaining the process within control limits is crucial to ensure consistent product quality and meet customer expectations. If the range of weights deviates significantly from the average range of **Y grams**, it may indicate that the process is out of control. In such cases, corrective actions need to be taken to investigate and address the underlying causes of the variability.

By continuously monitoring and adjusting the filling line, the Canine Gourmet Company can achieve the desired average weight per packet of **X grams**. This control ensures that the dog treats consistently meet the discriminating tastes of their canine customers and maintain the high standards of quality associated with the brand.

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Answer:

B. 85.6%

Step-by-step explanation:

Since we want to find the percentage, which is essentially a fraction, we will divide the area of the smaller frame by the area of the larger paper.

The paper and frame are both rectangles, so the area of a rectangle is denoted by A = lw, where l is the length and w is the width.

For the paper, the length is l = 8.5 and the width is w = 11. So:

A = lw

A = 8.5 * 11 = 93.5 inches squared

For the frame, the length is l = 8 and the width is w = 10. So:

A = lw

A = 8 * 10 = 80 inches squared

The percentage of the original sketch included in the frame would be:

(80 / 93.5) * 100 ≈ 85.6%

The answer is thus B.

~ an aesthetics lover

Answer:

The answer should be B. 85.6% hopefully this helped you!

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Domain: (-6, -1]

This is where the graph lines up with the x-axis.

Range: [-6, 4)

This is where the graph lines up with the y-axis.

See the two pictures for a visual reason why.

The estimated area of the unshaded rectangle is 5625 square inches.

The formula for calculating the area of a rectangle. Rectangle surface area. A = l × b.

Once the length and breadth of a rectangle are determined, the area is computed.

The area of a rectangle may be calculated by multiplying its length and width.

The estimated value of the length of the shaded square is: 11 inches

The estimated value of the area of the unshaded rectangle is: 5625 square inches.

To find the estimated length of the shaded square,

We can use the square root of the area:

√(125) = 11

To find the estimated area of the unshaded rectangle,

We can multiply the length by the width:

75 * 11 = 825

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Answer:

\(\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx = \frac{1}{8} \bigg( e^\Big{\frac{4}{25}} - e^\Big{\frac{4}{81}} \bigg)\)

General Formulas and Concepts:

Calculus

Differentiation

Derivative Property [Multiplied Constant]:                                                           \(\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)\)

Basic Power Rule:

Integration

Integration Rule [Fundamental Theorem of Calculus 1]:                                     \(\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)\)

Integration Property [Multiplied Constant]:                                                         \(\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx\)

U-Substitution

Step-by-step explanation:

Step 1: Define

Identify

\(\displaystyle \int\limits^9_5 {\frac{1}{x^3}e^\big{4x^{-2}}} \, dx\)

Step 2: Integrate Pt. 1

Identify variables for u-substitution.

Step 3: Integrate Pt. 2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

The forecast for the next period using the following weights: 0.3, 2, 0.5 is Option d. 421.

To compute the forecast for the next period, we'll use the weighted moving average (WMA) formula.WMA formula:

WMA = W1Yt-1 + W2Yt-2 + ... + WnYt-n

Where, WMA is the weighted moving average

W1, W2, ..., Wn are the weights (must sum to 1)

Yt-n is the demand in the n-th period before the current period

As we know Month 1 – 381, Month 2-366, and Month 3 - 348.

Weights: 0.3, 2, 0.5

We'll compute the forecast for the next period (month 4) using the data:

WMA = W1Yt-1 + W2Yt-2 + W3Yt-3WMA

= 0.3(381) + 2(366) + 0.5(348)WMA

= 114.3 + 732 + 174WMA

= 1020.3

Therefore, the forecast for the next period is 1020.3, which rounds to 421. Hence, option d is correct.

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The results obtained by central limit theorem are given below-

μ = 170 customers per day

σ = 45 customers per day

n = 31

\(\begin{aligned}&\mu_{x}=170 \\&\sigma_{x}=8\end{aligned}\)

The Central Limit Theorem proves that the distribution of a sample means of size n can be estimated to the normal distribution with mean  (μ) and standard deviation (σ) for one random normally distributed variable X, with mean (μ) and standard deviation (σ);

\(s=\frac{\sigma}{\sqrt{n}}\)

This Central Limit Theorem may also be applied to skewed variables if n is at least 30.

She observes that the rival business averages 170 clients per day, with a standard deviation of 45 clients.

Thus, \(\mu=170, \sigma=45\)

Let's say she selects a random sampling of 31 days.

So, n = 31

Now, the mean is according to the Central Limit Theorem is

\(\mu_{x}=170\), and

standard deviation = \(\sigma_{x}=\frac{45}{\sqrt{31}}=8\)

Therefore, by using central limit theorem the data is obtained as,

μ = 170 customers per day

σ = 45 customers per day

n = 31

\(\begin{aligned}&\mu_{x}=170 \\&\sigma_{x}=8\end{aligned}\)

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The complete question is-

A business woman wants to open a coffee stand across the street from a competing coffee company. She notices that the competing company has an average of 170 customers each day, with a standard deviation of 45 customers. Suppose she takes a random sample of 31 days. Identify the following to help her decide whether to open her coffee stand, rounding to the nearest whole number when necessary:

μ = _____customers per day

σ = _____customers per day

n = ____

\(\mu_{x}\) =____

\(\sigma_{x}\) = ____

Answer:

Step-by-step explanation:

1) a) r =  7 cm

 \(\sf \boxed{\text{Volume of sphere=$\dfrac{4}{3}\pi r^3$}}\)

                             \(\sf =\dfrac{4}{3}*3.14*7*7*7\\\\= 1436 \ cm^3\)

 \(\sf \boxed{\text{\bf Surface area of sphere = $4\pi r^2$}}\)

                                           = 4*3.14 * 7 * 7

                                           = 615.44 cm²

b) r= 8.4 cm

     \(Volume = \dfrac{4}{3}\pi r^3\)

                  \(\sf =\dfrac{4}{3}*\dfrac{22}{7}*8.4*8.4*8.4\\\\= 2483.7 \ cm^3\)

   Surface area = 4*3.14*8.4*8.4

                         = 887.04 cm²

      a) r = 6 cm

     \(\sf \boxed{\text{\bf Volume of hemisphere =$\dfrac{2}{3} \pi r^3$}}\)

                                                \(\sf =\dfrac{2}{3}*3.14*6*6*6\\\\= 452.16 \ cm^3\)

        \(\sf \boxed{\text{\bf Surface area of hemisphere=3 \pi r^2}}\)\(\sf \boxed{\text{\bf Surface area of hemisphere = $3 \pi r^2$}}\)

                                                            = 3 * 3.14 * 6 * 6

                                                             = 339.12 cm²

Answer:

I need more info

Step-by-step explanation:

Answer:

its A

Step-by-step explanation:

i literally just took the test

A clue that would help to find the speed of the current is that the rate of Chan's rowing in still water is 8 mph.

This concept comprises of 4 terminologies:

Given:

Speed of Chan's boat in still water = 8 mph

Time taken by Chan to row upstream from his house to the park = 3 h

Time taken by Chan to row downstream from the park to his house = 2 h

we have to find the speed of the current.

Let the speed of the current be v.

We know, Speed = Distance / Time

⇒ Distance = Speed × Time

Now, the distance between the house and the park is constant, hence the distance travelled upstream and downstream will be constant.

For upstream, speed of the boat is calculated as:

⇒ Speed = (speed of the boat in still water) - (speed of the current)

⇒ Speed = (8 - v)

Hence, distance is:

⇒ Distance = (8 - v) × 3              …(1)

Similarly for downstream, speed of the boat is:

⇒ Speed = (speed of the boat in still water) + (speed of the current)

⇒ Speed = (8 + v)

Distance will be:                          

⇒ Distance = (8 + v) × 2             …(2)

Now since the distance is equal we can equate the equation (1) and (2).

⇒ (8 - v) × 3 = (8 + v) × 2

⇒ 24 - 3v = 16 + 2v

⇒ 5v = 8

⇒ v = 1.6 mph

Hence, the speed of the current is 1.6 mph.

Here, we can observe that to solve this problem we need the time taken to cross along each stream and the speed of the boat in the still water.

The option: Chan rows from house to the park on Wednesday, gives information about the the distance travelled by the boat and it is  constant and cannot be used to deduce the speed of the current.

The option: The entire trip takes five hours, is not used anywhere to solve the problem, instead the separate times to cross each stream was required. Hence this option was also not sufficient.

Therefore, the rate of Chan's rowing in still water is 8 mph, is the clue that helps to solve this word problem.

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Based on the given information that 2 out of 20 sample points plotted on a control chart are beyond the control limits, the correct answer is D) The evidence is sufficient to indicate that the process is out of control.

Control charts are used to monitor and control processes, with control limits representing the expected boundaries for a process in control.

When data points fall outside these control limits, it indicates that the process is exhibiting variation beyond the expected range.

In this case, the occurrence of 2 out of 20 sample points beyond the control limits suggests that the process is not operating within the expected range of variation.

This provides sufficient evidence to indicate that the process is out of control.

Option B, stating that the evidence is sufficient to indicate the process is in control, is incorrect based on the information provided. The evidence supports the conclusion that the process is out of control, not in control.

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Answer: Mona wrote 21 checks during a month where her total fee was $12.52

Step-by-step explanation:

f = 10 + 0.12n

12.52 = 10 + 0.12n

\(\frac{2.52}{0.12}\) = \(\frac{0.12n}{0.12}\)

n = 21

Mona wrote 21 checks during a month where her total fee was $12.52

Answer:

??

Step-by-step explanation:

3.141592653589793238462643383279502884197169399375105820974944592307816406286208998628034825342117067982148086513282306647093844609550582231725359408128481117450284102701938521105559644622948954930381964428810975665933446128475648233786783165271201909145648566923460348610454326648213393607260249141273724587006606315588174881520920962829254091715364367892590360011330530548820466521384146951941511609433057270365759591953092186117381932611793105118548074462379962749567351885752724891227938183011949129833673362440656643086021394946395224737190702179860943702770539217176293176752384674818467669405132000568127145263560827785771342757789609173637178721468440901224953430146549585371050792279689258923542019956112129021960864034418159813629774771309960518707211349999998372978049951059731732816096318595024459455346908302642522308253344685035261931188171010003137838752886587533208381420617177669147303598253490428755468731159562863882353787593751957781857780532171226806613001927876611195909216420198938095257201065485863278865936153381827968230301952035301852968995773622599413891249721775283479131515574857242454150695950829533116861727855889075098381754637464939319255060400927701671139009848824012858361603563707660104710181942955596198946767837449448255379774726847104047534646208046684259069491293313677028989152104752162056966024058038150193511253382430035587640247496473263914199272604269922796782354781636009341721641219924586315030286182974555706749838505494588586926995690927210797509302955321165344987202755960236480665499119881834797753566369807426542527862551818417574672890977772793800081647060016145249192173217214772350141441973568548161361157352552133475741849468438523323907394143334547762416862518983569485562099219222184272550254256887671790494601653466804988627232791786085784383827967976681454100953883786360950680064225125205117392984896084128488626945604241965285022210661186306744278622039194945047123713786960956364371917287467764657573962413890865832645995813390478027590099465764078951269468398352595709825822620522489407726719478268482601

The output values of f(2), f(4) and f(-3) in the function f(x) = x² - 2x - 4 are -4, 4 and 11 respectively.

A function is simply a relationship that maps one input to one output.

Given the data in the question;

To determine the output value of f(2), f(4) and f(-3), replace all the occurrence of x with 2, 4, and -3 in the function and simplify.

For f(2),

f(x) = x² - 2x - 4

f(2) = (2)² - 2(2) - 4

f(2) = 4 - 4 - 4

f(2) = -4

For f(4),

f(x) = x² - 2x - 4

f(2) = (4)² - 2(4) - 4

f(2) = 16 - 8 - 4

f(2) = 16 - 12

f(2) = 4

For f(-3),

f(x) = x² - 2x - 4

f(-3) = (-3)² - 2(-3) - 4

f(-3) = 9 + 6 - 4

f(-3) = 9 + 2

f(-3) = 11

The output values of f(2), f(4) and f(-3) in the function f(x) = x² - 2x - 4 are -4, 4 and 11 respectively.

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The number of asymptotes for a large gain, k value in a unity negative feedback system with an open-loop transfer function is zero.

In a unity negative feedback system, the closed-loop transfer function is given by the equation: T(s) = G/(1+GH). Where G is the open-loop transfer function and H is the feedback transfer function. In this case, since the feedback transfer function is -1 (negative feedback), we have:T(s) = G/(1-G). For a large gain, k value, the open-loop transfer function G approaches infinity. Therefore, the closed-loop transfer function simplifies to: T(s) = infinity/(1-infinity) T(s) = infinity.

This indicates that the system has zero asymptotes, meaning there are no poles or zeros at infinity in the transfer function. The absence of asymptotes implies that the system is stable and able to provide a good response without any oscillations or overshoots. Therefore, a unity negative feedback system with an open-loop transfer function has no asymptotes for a large gain, k value.

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Answer:

7.833 yards²

Step-by-step explanation:

I can't take a pic but heres a link that does the math for you and explains. The top of the rectangular prism btw is called the surface area

https://www.omnicalculator.com/math/surface-area-rectangular-prism