Question 46: A figure has a perimeter of 112 units. What will the new perimeter be after a dilation with a scale factor of 1/4?
Can someone please help me?

According to the conversation we can infer that the information focused on the conversation of two people; one of them is studing for an exam.

To identify what is the conversation about we have to consider who is talking and what are the ideas that they share. In this case, we can infer that the main idea of this conversation is that one of them is studying for an exam this week.

Also, the second person is apologizing because he considered that he is distracting the other person. So, the correc information about de conversation is a short conversation about study.

Note: This question is incomplete. Here is the complete information:

Conversation:
Hello

Hello, How are you?

I am fine, and you?

i am fine too, What are you doing?

I am studing for an exam this week.

Oh, sorry I won´t distract you.

Don´t worry.

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Answer:

24 represents the initial admission cost to enter the amusement park.

Answer:

C polyatomic atoms

Step-by-step explanation:

Answer: x=3

Step-by-step explanation:  Hope I helped trust me I am really good at math.

Answer:

The pantograph is spring-loaded and pushes a contact shoe up against the underside of the contact wire to draw the current needed to run the train.    As the train moves, the contact shoe slides along the wire and can set up standing waves in the wires which break the contact and degrade current collection.

Step-by-step explanation:

Answer:

$7.50

Step-by-step explanation:

round 53.43 down to 50

tip = total cost * rate of tip

I hope this helped

The bookstore has 10 copies left.

Step- By- Step Explanation

After the first day, 1/3 of the original amount remained: (1/3)·45 = 15

After the second day, 2/3 of that amount remained: (2/3)·15 = 10

The value of the probabilities are

a. P(X < 4) = 0

b. P(X > 3.5) ≈ 0.796875

c. P(4 < X < 5) ≈ 0.5625

d. P(X < 4.5) ≈ 0.703125

e. P(X < 3.5 or X > 4.5) = 0

a. P(X < 4):

To calculate P(X < 4), we need to find the area under the curve of the function f(x) = x/8 for values of x less than 4. However, the given function is only defined for the range 3 < x < 5. Therefore, we cannot directly calculate P(X < 4) using this function. The probability of X being less than 4 is zero since the function does not cover that range.

b. P(X > 3.5):

To calculate P(X > 3.5), we need to find the area under the curve of the function f(x) = x/8 for values of x greater than 3.5. Since the function is defined for 3 < x < 5, we can calculate this probability by integrating the function over the range 3.5 to 5.

Integrating f(x) from 3.5 to 5:

∫[3.5, 5] (x/8) dx = [x²/16] evaluated from 3.5 to 5

= [(5²/16) - (3.5²/16)]

= (25/16) - (12.25/16)

= 12.75/16

= 0.796875

Therefore, P(X > 3.5) ≈ 0.796875.

c. P(4 < X < 5):

To calculate P(4 < X < 5), we need to find the area under the curve of the function f(x) = x/8 for values of x between 4 and 5. We can calculate this probability by integrating the function over the range 4 to 5.

Integrating f(x) from 4 to 5:

∫[4, 5] (x/8) dx = [x²/16] evaluated from 4 to 5

= [(5²/16) - (4²/16)]

= (25/16) - (16/16)

= 9/16

= 0.5625

Therefore, P(4 < X < 5) ≈ 0.5625.

d. P(X < 4.5):

To calculate P(X < 4.5), we need to find the area under the curve of the function f(x) = x/8 for values of x less than 4.5. We can calculate this probability by integrating the function over the range 3 to 4.5.

Integrating f(x) from 3 to 4.5:

∫[3, 4.5] (x/8) dx = [x²/16] evaluated from 3 to 4.5

= [(4.5²/16) - (3²/16)]

= (20.25/16) - (9/16)

= 11.25/16

= 0.703125

Therefore, P(X < 4.5) ≈ 0.703125.

e. P(X < 3.5 or X > 4.5):

To calculate P(X < 3.5 or X > 4.5), we can calculate the sum of probabilities P(X < 3.5) and P(X > 4.5). However, as mentioned earlier, the function f(x) = x/8 is not defined for values less than 3 or greater than 5. Therefore, the probability of X being less than 3.5 or greater than 4.5 is zero.

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The distance between the tractor and the bale at this moment is 1 meter.

To determine the distance between the tractor and the bale at the given moment, we can use the concept of relative motion.

The distance between the tractor and the bale is the difference in their positions. Since the tractor is moving at a speed of 3 m/s and the bale is rising at a speed of 2 m/s, their relative speed is the difference between the two speeds, which is 3 m/s - 2 m/s = 1 m/s.

To find the distance, we can use the formula:

Distance = Speed × Time

In this case, the relative speed is 1 m/s. Since the tractor and the bale are moving in the same direction, we can assume that their speeds are constant over the given time. Therefore, we don't need to consider the time in this calculation.

So, the distance between the tractor and the bale at this moment is 1 meter.

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Responda:

1075 tijolos

Explicação passo a passo:

Dado que:

Número de tijolos produzidos Mensalmente = 5.000 tijolos

A quantidade de tijolos produzidos por licença = 3925

O número de tijolos que ainda faltam no valor mensal desejado:

Quantidade de produção mensal - quantidade produzida por licença

5000 - 3925 = 1075 tijolos

When slave starting a disabled vehicle, the term that serves an important safety consideration is c. The slaving vehicle engine must be running while connecting the slave cable

The dead car is started while the live vehicle's engine is running by inserting a slave cable into the receptacle on each vehicle.

Vehicles with manual transmissions rely heavily on the clutch slave cylinder. When the pedal is depressed, the clutch is disengaged and the transmission is shifted thanks to the slave and clutch master cylinders.

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The given problem is a mixed integer programming problem that can be solved using the Branch and Bound algorithm. The objective is to maximize the expression Z = x1 + x2, subject to certain constraints.

The Branch and Bound algorithm is an optimization technique used to solve mixed integer programming problems. It systematically explores the solution space by dividing it into smaller subspaces (branches) and bounding the objective function value within each branch.

In this problem, we aim to maximize the expression Z = x1 + x2. The decision variables, x1 and x2, are subject to the following constraints:

1. 2x1 + 5x2 ≤ 1

2. 6x1 + 5x2 ≤ 30

3. x2 ≥ 0

4. x1 ≥ 0 and integers

To apply the Branch and Bound algorithm, we start with an initial feasible solution and compute its objective function value. Then, we divide the solution space into branches based on the integer constraints. Each branch represents a possible combination of integer values for the variables.

At each branch, we calculate the objective function value and update the current best solution. If the objective function value at a branch is less than the current best solution, we prune that branch, as it cannot yield an optimal solution. If the branch satisfies all constraints and has a higher objective function value than the current best solution, we update the best solution.

By systematically exploring and pruning branches, the Branch and Bound algorithm eventually converges to the optimal solution, maximizing the expression Z = x1 + x2 while satisfying the given constraints.

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The image of point A after it is dilated with a scale factor 3 is (6, 12)

Dilation is a transformation, which is used to resize the object.

A scale factor is when you enlarge a shape and each side is multiplied by the same number. This number is called the scale factor.

Let the coordinates of A are (2, 4)

We have to find the coordinates of point A after dilation with scale factor 3

A'=(3×2, 3×4)

=(6, 12)

Hence,  the image of point A after it is dilated with a scale factor 3 is (6, 12)

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Answer: Get a snack.

Answer:

Rate of boat in still water = 56 km per hour

Rate of the current = 8 km per hour

Step-by-step explanation:

This question is incomplete; to understand how to solve these questions let the question is,

A motorboat takes 4 hours to travel 192 km going upstream. The return trip takes 3 hours going downstream. What is the rate of the boat in still water and what is the rate of current.

Let the rate of current = u km per hour

And the rate of boat in still water = v km per hour

Then going upstream, rate of the boat = Rate of the boat in still water - Rate of current

= (v - u) km per hour

Similarly, going downstream, rate of the boat = Rate of boat in still water + Rate of current

= (v + u) km per hour

Since, the boat takes 4 hours upstream,

By using the formula,

Rate = \(\frac{\text{Distance}}{\text{Time}}\)

Distance traveled = Rate × Time

For upstream,

192 = 4(v - u)

v - u = 48 ------(1)

For downstream,

192 = 3(v + u)

v + u = 64 ------(2)

By adding equation (1) and (2),

(v - u) + (v + u) = 48 + 64

2v = 112

v = 56 km per hour

From equation (1),

56 - u = 48

u = 56 - 48

u = 8 km per hour

Rate of boat in still water = 56 km per hour

Rate of the current = 8 km per hour

Answer:

Step-by-step explanation:

Dont do it. Just take the detention

The magnitude of the force required to prevent the car from rolling down the hill is 1578.88 Newton.

In accordance with Newton's Second Law of Motion, the force acting on this car is equal to the horizontal component of the force (Fx) that is parallel to the slope:

Fx = mgcosθ

Fx = Fcosθ

Where:

Note: 3500 lbs to kg = 3500/2.205 = 1587.573 kg

By substituting the given parameters into the formula for the horizontal component of the force (Fx), we have;

Fx = 1587.573cos(6)

Fx = 1578.88 Newton.

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The magnitude of the force required to prevent the car from rolling down the hill is approximately 367.01 lbs.

To find the magnitude of the force required to prevent the car from rolling down the inclined hill, we can analyze the forces acting on the car.

The weight of the car acts vertically downward with a magnitude of 3500 lbs. We can decompose this weight into two components: one perpendicular to the incline and one parallel to the incline.

The component perpendicular to the incline can be calculated as W_perpendicular = 3500 * cos(6°).

The component parallel to the incline represents the force that tends to make the car roll down the hill. To prevent this, an equal and opposite force is required, which is the force we need to find.

Since we are ignoring friction, the force required to prevent rolling is equal to the parallel component of the weight: F_required = 3500 * sin(6°).

Calculating this value gives:

F_required = 3500 * sin(6°) ≈ 367.01 lbs (rounded to 2 decimal places).

Therefore, the magnitude of the force required to prevent the car from rolling down the hill is approximately 367.01 lbs.

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Answer:

  (a, b) alternate interior angles at M and N, and at A and B are congruent

  (c) the triangles are congruent by SAS and by ASA (and MX = NX)

  (d) angles are no longer congruent, so the triangles are not congruent. The radii are given as congruent, but the chords cannot be shown congruent.

Step-by-step explanation:

Given same-size circles A and B, externally tangent to each other at X, each with chords MX and NX, you want to know what can be concluded if AM║BN, and what is unprovable if those segments are not parallel.

The circles being the same size means all the radii are congruent. This is shown by the single hash marks in the attached diagram.

Alternate interior angles where a transversal crosses parallel lines are congruent. If AM║BN, this means the angles marked with a single arc are congruent, and the angles marked with a double arc are congruent. These are the alternate interior angles at transversal MN and at transversal AB.

If AM║BN, in addition to the given congruences, we also know ...

∆AMX ≅ ∆BNX by SAS or ASA (take your pick).

If AM and BN are not parallel, MN is not a straight line through X, the angles at A and B are not congruent, and the angles at M and N are not congruent. (We assume segment AB still goes through X.)

__

Additional comment

Triangles MAX and NBX are isosceles, so their base angles are congruent. If X lies on MN, then AM and BN must be parallel, since the vertical angles at X will be congruent along with the other base angles at M and N. If AM and BN are not parallel, point X cannot lie on segment AB.

4s+8.5a>=460

s+a<=79

s=53

4*53+8.5a>=460

212+8.5a>=460

8.5a>=248

a>=29.1765 --> 30

30+53 is 83, which is greater than 79, so this is not possible.

If 53 tickets were sold to students, it is not possible to meet the minimum amount of money the drama club needs to make. They need to either sell less tickets to the students, or have a larger venue.

Answer:

the measure of the missing angle would be 65⁰

Step-by-step explanation:

that square symbol in the corner represents 90⁰

90⁰-25⁰= 65⁰

To find the marginal probability mass function of x and y, we sum f(x, y) over the values of y and x, respectively. For x = 1, we have f(1,0) = 0 and f(1,1) = 1/8, so the marginal probability mass function of x is given by:

f(x) = Σ f(x,y) = f(1,0) + f(1,1) + f(2,0) + f(2,1) = 0 + 1/8 + 0 + 2/8 = 3/8

Similarly, for y = 0, we have f(1,0) = 0 and f(2,0) = 2/8, so the marginal probability mass function of y is given by:

f(y) = Σ f(x,y) = f(1,0) + f(1,1) + f(2,0) + f(2,1) = 0 + 1/8 + 2/8 + 1/8 = 1/2

The expected value of x is given by:

E[X] = Σ x f(x) = 1(3/8) + 2(5/8) = 1.625

The expected value of y is given by:

E[Y] = Σ y f(y) = 0(1/2) + 1(1/2) = 0.5

The covariance between x and y is given by:

Cov[X,Y] = E[XY] - E[X]E[Y]

We can find E[XY] by summing xyf(x,y) over all values of x and y:

E[XY] = Σ Σ xy f(x,y) = 1(0) + 1(1/8) + 2(0) + 2(2/8) = 1/2

Substituting in the values we have found, we get:

Cov[X,Y] = E[XY] - E[X]E[Y] = (1/2) - (1.625)(0.5) = -0.25

Therefore, the covariance between x and y is -0.25.

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To have a valid 98% confidence interval based on a sample of size n, it is necessary to assume that the population has an approximately normal distribution (option A).

The margin of error in a confidence interval is influenced by the sample size and the confidence level. The margin of error is inversely proportional to the square root of the sample size. This means that increasing the sample size (option A) will result in a smaller margin of error, as the square root of a larger number is larger than that of a smaller number.

On the other hand, the margin of error is directly proportional to the critical value, which is determined by the confidence level. The higher the confidence level, the larger the critical value and consequently, the larger the margin of error. Thus, decreasing the confidence level (option D) will result in a larger margin of error.

Therefore, the options that will result in a larger margin of error are B and D: decreasing the sample size while keeping the same confidence level, and decreasing the confidence level while keeping the same sample size.

It's important to note that the validity of a confidence interval relies on certain assumptions. In this case, to have a valid 98% confidence interval based on a sample of size n, it is necessary to assume that the population has an approximately normal distribution (option A). This assumption is required for the central limit theorem to hold, which allows the sampling distribution of the sample mean to approximate a normal distribution. Options B, C, and D do not accurately describe the assumptions necessary for the validity of the confidence interval.

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Answer:

66666699999

Step-by-step explanation:

Answer:

8 paint colors

Step-by-step explanation:

5 1/3= 16/3

2/3 cup of water can make one color, which means 8 colors can be made with 16/3 cups of water.

The question is incomplete. The complete question is :

A bulb can either be on or off. A board contains 20 bulbs connected to a randomization circuit that lights up a random sequence every time it is turned on. What is the probability that all the lights will switch on ?

Solution :

It is given that :

There is board connected to = 20 bulbs

And one can either be put ON or put OFF.

Therefore the chance that a bulb is ON = \($\frac{1}{2}$\)

It is given that every time a bulb turns ON, the board lights up in a random sequence.

Therefore, the probability of all the lights to be switched ON is given by :

\($=\left(\frac{1}{2}\right)^{20}$\)

\($=\frac{(1)^{20}}{(2)^{20}}$\)

\($=\frac{1}{1048576}$\)

The solution is: 3.7%, is the probability that the next customer will be a woman who requests a convertible.

Here, we have,

given that,

At a car rental office, 63% of the customers are men and 37% are women.

If 25% of people request a compact car, 37% request a full-sized, 10% request a convertible,16% request an SUV, and 12% request a luxury car

As per given

P(woman)= 37%

P(convertible) = 10%

So combined probability is:

P = 37%*10%

  = 37%*0.1

  = 3.7%

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complete question:

At a car rental office, 63% of the customers are men and 37% are women. If 25% of people request a compact car, 37% request a full-sized, 10% request a convertible,16% request an SUV, and 12% request a luxury car, what is the probability that the next customer will be a woman who requests a convertible?

Answer:

B

Step-by-step explanation:

the general slope intercept form is

y = ax + b

a is the slope, b is the y-intercept (the y value when x = 0).

a parallel line must have the same slope (1/2).

for b we simply put the x and y values of the given point into the equation

1 = 1/2 × -8 + b = -4 + b

b = 5

therefore,

y = 1/2 x + 5

is the correct solution.

the surface integral. s (x + y + z) ds, s is the parallelogram with parametric equations x = u + v, y = u − v, z = 1 + 2u + v is 10\(\sqrt{14}\)

The surface element is

dS = || ∂r/∂u  x  ∂r/dv || du dv

where

r (u, v) = x (u, v) i + y (u, v) j + z (u, v) k

r (u, v) = (u + v) i + (u - v) j + (1 + 2u + v) k

is the vector parameterization for the surface S.

The normal vector to the surface is

∂r/∂u  x  ∂r/dv

… = (i + j + 2 k)  x  (i - j + k)

… = 3 i + j - 2 k

and has norm

|| ∂r/∂u  x  ∂r/dv || = √(3² + 1² + (-2)²) = √(14)

Now compute the integral:

∫∫ (x + y + z) dS = √(14) ∫₀¹ ∫₀² ((u + v) + (u - v) + (1 + 2u + v)) du dv

… = √(14) ∫₀¹ ∫₀² (3u + v + 1) du dv

… = √(14) ∫₀¹ (3/2 u² + uv + u) |₀² dv

… = √(14) ∫₀¹ (8 + 2v) dv

… = √(14) (8v + 2v²) |₀¹

… = 10 √(14)

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