Answer:
The answer is "\(\bold{9.09\times 10^6 \frac{kg}{hour}}\)".
Explanation:
For the reference table we get:
\(h1 = 2410 \frac{kJ}{kg} \ , at \ \ \\\\ \ P = 0.08 \ bar \ and \ \ quality = 0.932\)
Through steam tables, they get:
\(\ h2 = 173.9 \frac{kJ}{kg} \ on\\\\ \ P = 0.08 \ bars \ \ \ but \ quality = 0 (sat.liquid),\)
Water power transfer = \(\ 3.4 \times 10 ^ 5 \times (2410-173.9)\\\)
It should be comparable to the water enthalpy:
\(m_{water}\times Cp\times (T2-T1)\\\\For \ eg:\\\\ = 3.4 \times 10 ^ 5\times (2410-173.9) \\\\ = m_{water}\times4.18\times(35-15)\\\)
\(m_{water}=9.09\times 10^6 \frac{kg}{hour}\)
40. AASHTO assumes a deceleration value in calculating SSD of:
a. 14 ft /sec2
b. 11.2 ft /sec2
c. 9.6 ft /sec2
d. 10.2 ft /sec2
AASHTO assumes a deceleration value in calculating stopping sight distance (SSD) of B. 11.2 ft/s^2. This doesn't take any road defects into account.
the voltage valve at which a zirconia O2S switches from rich to lean and lean to rich is
A) 0.5v (500mv)
B) 0.45v (450mv)
C) 0.25v (250mv)
D) 0.90v (900)
In order to be a Mechanical Engineer, you need to:
1. Have a Bachelor's Degree
2. Have a Master's Degree
3. Have a Ph.D.
Answer:
3
Explanation:
it is compulsory to have a bachelor's degree
At steady state, air at 200 kPa, 325 K, and mass flow rate
of 0.5 kg/s enters an insulated duct having differing inlet
and exit cross-sectional areas. The inlet cross-sectional area is
6 cm26cm
2. At the duct exit, the pressure of the air is 100 kPa and the velocity is 250 m/s. Neglecting potential energy
effects and modeling air as an ideal gas with constant cp=1.008 kJ/kg⋅Kc
p =1.008kJ/kg⋅K, determine
(a) the velocity of the air at the inlet, in m/s.
(b) the temperature of the air at the exit, in K.
(c) the exit cross-sectional area, in cm2
(a) the velocity of the air at the inlet, in m/s.
(b) the temperature of the air at the exit, in K.
(c) the exit cross-sectional area, in cm
1. The only purpose of a personal fall arrest system is to
A) Keep workers from falling
B) Hoist materials
C) Avoid having to use a
net
D)All of the above
✅C) Avoid having to use a net ✅
IamSugarBee
eggzOG43199
:) it has to be more than 20 characters so I'm just saying this
Answer:
giberishgiberishgiberishgiberishgiberishgiberishgiberishgiberishgiberish
Explanation:
i have no idea what the question is but do u 4 real need help?
You are getting ready to transport troops in an M1152 configured with cargo cover and troops seats. Which of the following should you do before starting out?
Answer:
I believe it would be to lower the troop seats.
Explanation:
Why does a foil airplane fly farther than a paper one?
A foil airplane is typically more aerodynamic than a paper airplane. It has a smoother surface, is more rigid, and can be shaped to generate lift more efficiently.
When thrown, a foil airplane experiences less air resistance, which allows it to travel farther and faster through the air. Additionally, a foil airplane is typically heavier than a paper one, which means it has more momentum and can fly through turbulence more easily. The shape of the wings also plays a role. Foil airplanes can have wings with a curved shape that generate lift more effectively, while paper airplanes typically have flat wings that don't produce as much lift. Overall, the design of a foil airplane is optimized for flight performance, while a paper airplane is more of a simple toy.
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which condition is correct for a firm wanting to maximize profit: which condition is correct for a firm wanting to maximize profit: mpk > mrpk mrp = mc mpl = mrp mpl = mc
The correct condition for a firm wanting to maximize profit is "MRP = MC".
The marginal revenue product (MRP) is the additional revenue produced by hiring an additional unit of input (such as labour or capital) in a perfectly competitive market where companies are price takers.
The increased expense incurred by using an additional unit of input is represented by the marginal cost (MC).
A company should keep adding employees until the marginal revenue product (MRP) matches the marginal cost (MC) in order to maximise profits.
This requirement guarantees that the company is using its resources effectively and making the most profit feasible.
Therefore, for a company that wants to maximise profit, the correct condition is "MRP = MC".
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The top of a ladder weighing 20kg and 6m long rests against a vertical wall and the foot of the ladder on a horizontal floor. For the wall, f=0.15, and for the floor f=0.20. How far up the ladder can a man weighing 60kg go before the ladder begins to slip?
The ladder distance a man weighing 60kg go before the ladder begins to slip is 2.973m.
What is friction?
The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction.
There are various kinds of friction: Two solid surfaces in touch are opposed to one another's relative lateral motion by dry friction.
Here, it is given that:
Weight of man = 20kg
\(N_1=f_aMg\\N_2=f_bMg\)
Momentum = 0
So,
\(N_1-N_2=-WgX\)
\((f_a-f_b)20=-60X\)tanФ
(0.15 - 0.02)20 = -60X x 3/5
x = 1/36
x = 0.027
Now, the distance will be 3 - x = 2.973m.
Thus, the answer is 2.973m.
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determine the magnitude of the resultant force acting on the pipe assembly.(figure 1) express your answer with the appropriate units. activate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type fr
The magnitude of the resultant force acting on the pipe assembly is 581.2 N. The appropriate units for this answer are newtons (N).
Explain magnitude of the resultant force acting on the pipe assembly in Figure 1?To determine the magnitude of the resultant force acting on the pipe assembly in Figure 1, we need to use the formula:
|FR| = sqrt(F1^2 + F2^2 + 2*F1*F2*cosθ)
where F1 and F2 are the magnitudes of the two forces acting on the pipe assembly and θ is the angle between them.
Using the given values in Figure 1 and assuming that the forces are in the same plane, we can find:
F1 = 300 N
F2 = 450 N
θ = 60 degrees
Plugging these values into the formula, we get:
|FR| = sqrt(300^2 + 450^2 + 2*300*450*cos60)
|FR| = sqrt(90000 + 202500 + 45000)
|FR| = sqrt(337500)
|FR| = 581.2 N (rounded to one decimal place)
Therefore, the magnitude of the resultant force acting on the pipe assembly is 581.2 N. The appropriate units for this answer are newtons (N).
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How much wood is needed to cut 6 pieces, 4 1/2 inches long for a project. the saw blades kerf is 1/8 of an inch.
The total length of the wood needed will be 27 inches.
How to calculate the length?From the information given, it was stated that each wood is about 4 1/2 inches and that 6 pieces will be needed.
The length of the total woods needed will be:
= 4 1/2 × 6
= 9/2 × 6
= 27 inches.
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Auto transformer starting may use its _____ advantage to provide more current on the load side of the transformer than on the line side
Autotransformer starting may use it "turns ratio" advantage to provide more current on the load side of the transformer than on the line side.
They have a number of advantages over traditional transformers, including size, weight, and cost savings.
One of the advantages of an autotransformer is its "tapping" advantage, which allows it to provide more current on the load side of the transformer than on the line side. This is because the autotransformer uses a single winding, and the load is connected to a tap that is located closer to the end of the winding than the tap that is connected to the line. By using this tapping advantage, an autotransformer can provide a greater amount of voltage or current to the load without drawing as much power from the line, which can result in energy savings and improved efficiency.
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Which step in the reverse-engineering process involves the identification of subsystems and their relationship to one another?
The answer is analyze
the constructor should take in one argument: a list of the number of sides (n) for each of the dice. each dice bag should have one field: a list of all of its dice.
In computer programming, a dice is often simulated using a random number generator. The number of sides on the dice is determined by the range of numbers generated.
The constructor for creating a dice bag should take in a list of the number of sides for each of the dice. This means that when you create a new dice bag object, you need to pass in a list of integers, where each integer represents the number of sides for a particular die in the bag.
Once you have this list, the constructor should create a new field for the dice bag object, which is itself a list of all the dice in the bag. To do this, you would need to iterate through the list of integers passed in as the argument, and for each integer n, create a new die object with n sides and add it to the list of dice for the bag.
Overall, the constructor would look something like this:
```
class DiceBag:
def __init__(self, dice_sides):
self.dice = []
for sides in dice_sides:
self.dice.append(Die(sides))
```
Here, `dice_sides` is the list of integers representing the number of sides for each die in the bag, and `Die` is the class representing a single die object. The `__init__` method creates a new list called `self.dice` and then loops through `dice_sides`, creating a new `Die` object with the appropriate number of sides and adding it to the `self.dice` list.
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what could happen if the engine was uncowled during the starting and operating procedures
If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity.
What is the engine starting procedure?Closing the throttle, turning off the fuel pump, setting the mixture control to idle cutoff, and simply cranking the engine is the most reliable hot start method I've found.
What is the procedure for engine failure?If an engine fails during rollout or just before takeoff, immediately shut both throttles and land the aircraft safely. Before reaching a safe single engine speed right away after takeoff, drop your nose to increase velocity. If you are unable to climb, close both throttles and land straight ahead.
What happens if engine fails during take off?The typical practice for the majority of aircraft would be to abandon takeoff if an engine failed during takeoff. In small aircraft, the pilot should turn the throttles down to idle, activate the speed brakes (if provided), and apply the brakes as needed if the engine fails before VR (Rotation Speed).
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Anthony and Angel are making plans for Friday. Anthony wants to go bowling. Angel doesn't bowl well and prefers to go ice-skating at the mall.
Anthony wants Angel to have a good time so he agrees ice-skating will be fun for both of them. Anthony's decision to go ice-skating is an example
of
O evaluation
O arbitration
Omed ation
O compromise
Answer:
4. Compromise
Explanation:
A compromise is when the two disagreeing parties give up something to make a conclusion that both are satisfied with. In this case, Anthony wants Angel to have a good time, so he gives up his bowling.
Allura Red Moles
Question of the Day {QOD}:
If you decided to drink massive amounts of Cherry Kool-AidTM on a dare, would you die from Allura Red toxicity or water intoxication first?
5. Answer the Question of the Day. Support your answer with specific evidence from your experimentation including LD50 calculations. In your discussion, calculate both the amount of grams and moles of Allura red in Kool-Aid as well as the volume of Kool-Aid you would need to ingest to reach the median lethal dose of Allura red
The concentration of Allura red used was 1.89x10^-4 M
Kool aid absorbance (after dilution: 1mL kool aid, 9mL water): 0.453
Kool aid concentration: 1.97x10^-4 M
LD50 water: 90g/kg
LD50 (rats and mice): 6,000 - 10,000 mg/kg
Answer:
Die of intoxication by water first
Explanation:
We assume that the weight of the man is 154.35 pounds which is 70 kg
LD50 water = 90g per kg
Maximum concentration = 90x70
= 6300grams
Convert grams to liters
6300/100
= 6.3 litres
From here we get amount of kool aid
6.3 x 1.97x10^-4
= 1.24x10^-3
= 1.24grams
1.24 grams is below 420 kool aid is lower than LD50 with about 6 grams for 1 kg (6x70kg = 420). So 420 is lethal dose. But 1.24 is less than this so the man has to die of water intoxication first.
The angle of attack of a wing directly controls the A) angle of incidence of the wing. B) amount of airflow above and below the wing. C) distribution of pressures acting on the wing.
The angle of attack of a wing directly controls the C) distribution of pressures acting on the wing.
When the angle of attack of a wing is increased, the air moving over the curved upper surface of the wing must travel a greater distance and faster than the air moving beneath the wing's flat lower surface. This creates an area of lower air pressure above the wing and an area of higher air pressure beneath the wing, resulting in lift. The greater the angle of attack, the greater the lift produced.
However, if the angle of attack is too great, the airflow over the wing may separate, causing a loss of lift and potentially leading to a stall. Therefore, proper control of the angle of attack is crucial for safe and efficient flight.
Option C is answer.
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Tech a says that the oxygen sensor is part of the feedback system for the engine management system. tech b says that long-term fuel trims that are positive
means that the pcm is leaning out the fuel mixture from the base pulse-width setting who is correct?
o tech a
o tech b
o both a and b
o neither a nor b
Answer:
Both Tech A and Tech B are correct. The oxygen sensor is indeed a part of the feedback system for the engine management system. The oxygen sensor measures the amount of oxygen in the exhaust gas and sends this information to the powertrain control module (PCM). Based on this information, the PCM can adjust the fuel mixture to ensure that it is optimally balanced for the current driving conditions.
Long-term fuel trims refer to the adjustments that the PCM makes to the fuel mixture over an extended period of time. Positive long-term fuel trims indicate that the PCM is leaning out the fuel mixture by reducing the amount of fuel injected into the engine. This is typically done in order to compensate for a condition that is causing the engine to run rich (too much fuel in the mixture).
Explanation:
A logic circuit with 3 gates and 2 inputs. The circuit will be read from the final output to the inputs.
The final AND gate has two inputs, the gate has output R.
The first input to the final AND gate is the output from an OR gate.
The OR gate has two inputs.
The first input to the OR gate is P.
The second input to the OR gate is Q.
The second input to the final AND gate is the output from a NOT gate.
The NOT gate has one input.
The input to the NOT gate is Q.
input signals:
P = 0 and Q = 1
R = __________-
Answer:
R = 0
Explanation:
The output R is the result of the function ...
R = (P+Q)·Q'
This simplifies to ...
R = PQ' + 0
R = PQ'
The result R will be the AND of P=0 and Q'=(1-1)=0. Any AND function with a 0 input will have a 0 output.
R = 0
Determine the critical load if the bottom is fixed and the top is pinned. ewew = 1. 6 ×(10)3ksi×(10)3ksi ,σyσy = 5 ksiksi
Critical load Fcr or buckling load is the value of load that causes the phenomenon of change from stable to unstable equilibrium state.
With that beign said, first it is neessary to calculate the moment of inercia about the x-axis:
\(Ix= \frac{db^3}{12}\\ Ix = \frac{2.(4)^3}{12} = 10.667in\)
Then it is necessary to calculate the moment of inercia about the y-axis:
\(Iy = \frac{db^3}{12}\\ Iy = \frac{4.(2)^3}{12} = 2.662in\)
Comparing both moments of inercia it is possible to assume that the minimun moment of inercia is the y-axis, so the minimun moment of inercia is 2662in.
And so, it is possible to calculate the critical load:
\(Pc\gamma = \frac{2046\pi ^2E.I}{L^2} \\Pc\gamma= \frac{2046.\pi ^2.(1,6.10^3.10^3).2662}{(10.12)^2} \\Pc\gamma= 5983,9db\)
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is the language composed of all strings over the alphabet {a,b} that contain an odd number of a's a regular language? if so, show why. note, again, that you may use any line of argument from the slides on regular languages, e.g., by (a) using the properties on slide 4
Yes, {a,b},L is {w|w contains more 1s than 0s}. Idea: this is similar to the language where the ... a's and b's differ, unioned with all strings not of the form aibj.
What is the regular expression for a language that at least has two A's in it?This language requires at least two a's in a string. Given that any string of b's can be positioned in front of the first a, behind the second a, or in between the two a's, and given that the regular expression b* can be used to represent any string of b's, b*a b*a b* is a regular expression for this language.
The regular phrase (a + b)* (aa + ba + bb)b)(a + b)* (aa + ba + bb) + a + b + c)b* ab* ad)b* aa b* corresponds to the language of all strings over the alphabet "a, b."
The expression "a,b" =,L i="w|w has more 1s than 0s" Idea: Unioning any strings that are not of the form aibj, this is akin to the language where the... a's and b's differ.
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A 4 stroke over-square single cylinder engine with an over square ratio of 1.1,the displacement volume of the engine is 245cc .The clearance volume is 27.2cc the bore of this engine is ?
Answer:
10.007
Explanation:
Assuming we have to find out the compression ratio of the engine
Given information
Cubic capacity of the engine, V = 245 cc
Clearance volume, V_c = 27.2 cc
over square-ratio = 1.1
thus,
D/L = 1.1
where,
D is the bore
L is the stroke
Now,
Volume of the engine V =\(\frac{\pi}{4} D^2L\)
plugging values we get
245 = \(\frac{\pi}{4} D^3/1.1\)
Solving we get D =7 cm
therefore, L= 7/1.1 =6.36 cm
Now,
the compression ratio is given as:
r =(V+V_c)/V_c
on substituting the values, we get
r = (245+27.2)/27.2 =10.007
Hence, Compression ratio = 10.007
(a) Demonstrate that the CPR is related to corrosion current density i (A/cm²) through the expression: KAi/ CPR = np Where CPR = the corrosion penetration rate, K is a constant, A is the atomic weight of the metal experiencing corrosion, n is the number of electons associated with the ionization of each metal atom, and p is the density of the metal. b. Calculate the value of the constant K for the CPR in mpy and i in µA/cm² (106 A/cm²).
The expression linking the corrosion penetration rate (CPR) to the corrosion current density (i) is given by KAi/CPR = np, where K is a constant, A is the atomic weight of the metal, n is the number of electrons involved in the ionization of each metal atom, and p is the density of the metal. To calculate the value of the constant K for CPR in milli-inches per year (mpy) and i in microamperes per square centimeter (µA/cm²), additional information is required.
The expression KAi/CPR = np relates the corrosion penetration rate (CPR) to the corrosion current density (i). The constant K in this expression represents the proportionality constant between the two variables. To calculate the value of K for the CPR in mpy and i in µA/cm², additional information is needed.
The constant K can be determined by rearranging the equation as K = (CPR * np) / (Ai). To calculate K, you would need to know the corrosion penetration rate (CPR) in mpy, the atomic weight of the metal (A), the number of electrons associated with the ionization of each metal atom (n), and the density of the metal (p).
Once you have the necessary values, you can substitute them into the equation to calculate the constant K. The resulting value of K will have units of mpy/(µA/cm²). Keep in mind that the units of CPR and i must be consistent with mpy and µA/cm², respectively, to obtain the correct value for K.
In summary, the expression KAi/CPR = np relates the corrosion penetration rate (CPR) to the corrosion current density (i), where K is a constant, A is the atomic weight, n is the number of electrons involved in ionization, and p is the density of the metal. To calculate the value of K in mpy and i in µA/cm², the specific values of CPR, A, n, and p are required to substitute into the equation and solve for K.
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Computer Science question
Answer: а в г
Explanation:
IF YOUR VEHICLE BREAKS DOWN, YOU SHOULD?
Answer:
1. TURN ON YOUR HAZARD/EMERGENCY LIGHTS
Turn on your hazard lights to warn other drivers as soon as you sense something's wrong. Keep them on until help arrives, recommends the National Motorists Association (NMA).
2. SLOW DOWN AND PULL OFF THE ROAD
Aim for the right shoulder of the road. Consumer reports recommends that you pull over to a safe, flat location that is as far away from moving traffic as possible.
3. TURN YOUR WHEELS AWAY FROM THE ROAD AND PUT ON THE EMERGENCY BRAKE
The California Department of Motor Vehicles (DMV) recommends pulling your emergency brake, sometimes called the parking brake. If you have to park on a hill or slope, turn the car's wheels away from the road to help prevent the care from rolling into traffic, says the California DMV.
4. STAY IN YOUR VEHICLE
If you're on a highway or crowded road, the Insurance Information Institute (III) recommends that you avoid getting out of your vehicle to look at the damage or fix a mechanical problem. If you need to get out of the car, get your vehicle to a safe place and make sure the road around you is completely clear. If you're stopped on the right-hand side of the road, get out through the passenger-side door.
5. BE VISIBLE
Once you're safely out of the vehicle, prop up your hood to let other drivers know they should proceed with caution. This will alert other drivers that you're broken down, according to the NMA.
6. SET UP FLARES OR TRIANGLES
Place flares or triangles with reflectors behind your car to alert other drivers to the location where you've stopped, says the III.
7. CALL FOR HELP
Call or use an app to get a tow truck, mechanic or roadside assistance to come help. your insurance company or other provider who may be able to help. If you're in an emergency situation or are not sure who to contact, call 911 or the local police for help.
Hope this helps :)
one inflight visual indication of possible wind shear is virga at the cloud base.
One inflight visual indication of possible wind shear is Virga at the cloud base, it refers to streaks or wisps of precipitation that fall from a cloud but evaporate before reaching the ground.
It appears as a gray or dark curtain-like formation hanging below the cloud base. When virga is observed at the cloud base during flight, it can be a significant indication of wind shear in the vicinity. Wind shear refers to a sudden and significant change in wind direction or speed over a short distance. It can occur vertically or horizontally and is commonly associated with weather phenomena such as thunderstorms, microbursts, or strong frontal systems.
Wind shear can pose significant risks to aircraft, especially during takeoff, landing, or low-level flight. The presence of virga at the cloud base suggests a dry layer of air between the cloud and the ground. This dry layer can be indicative of a downdraft or sinking air associated with a thunderstorm or a microburst. As the downdraft descends from the cloud base, it evaporates the precipitation before it reaches the ground, creating the virga formation.
Inflight visual indications of virga at the cloud base alert pilots to the potential presence of wind shear and associated hazardous conditions. The downdrafts associated with Virga can lead to sudden changes in wind speed and direction, which can affect aircraft performance, stability, and control. Pilots should exercise caution and be prepared to encounter turbulence, rapid changes in airspeed, and potential fluctuations in aircraft altitude.
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which type of building construction can include materials with no fire-resistance ratings in limited quantities?
The type of type of building construction can include materials with no fire-resistance ratings in limited quantities is type 2.
Although many buildings appear to be similar at first appearance, their cost and durability—particularly in an emergency—are affected by the underlying materials. Building codes categorize all structures into Types 1 through 5, and each Type discloses important details like fire-resistance.
Some contemporary structures are now stronger and less expensive to construct. Engineered wood and synthetic plastics, which burn readily, cause quick collapses and present significant risks for firefighters.
Type 1 constructions, which are the most fire-resistant buildings, are made of shielded steel and concrete because they can sustain high temperatures without collapsing. Type 5 constructions, on the other hand, are the least fire-resistant since they are built of flammable materials, are lightweight, and they burn out quickly. Type 2 constructions, modern structures with metal roofs and tilt-slab or reinforced masonry walls.
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In the High Low Logic Index low levels are bearish and high levels are bullish, generally True False
Answer:
True
Explanation:
Logic index is selection of values based on the logical streams. The values appear on the logical array. The levels are determined on the market investment performance. If there are many buyers available in the market the index will be high and the market will be bullish. If there are few or no investors available the market index will be low which means the market is bearish.